Problem with answer in my code

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Anastasiia Hanchevska
回答： Elijah Gendron 2023-3-16
Ran in:
I have this code below, and it should give answer like this at the top of the screenshot, but it giving this another answer, idk what problem. I need code where i will get 5 vectors(cause i have 5 index in matrix) and every vector should have one max value, for example if we will take first vector it will have the max number from first index and the min number in each subsequent index, second vector will have max number from second index and min number in all others vectors. Hope you will understand
X = [2 5; 3 6; 1 7; 3 6; 1 5];
[m, n] = size(X);
for i = 1:n
temp = X(:, i);
for j = 1:m
if X(j, i) == max(temp)
temp(j) = min(temp);
elseif X(j, i) == min(temp)
temp(j) = max(temp);
end
end
eval(sprintf('X%d = temp'';', i));
end
% show results
for i = 1:n
eval(sprintf('disp([''X%d = '', mat2str(X%d)]);', i, i));
end
X1 = [2 1 3 1 3] X2 = [7 6 5 6 7]

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回答（1 个）

Elijah Gendron
Elijah Gendron 2023-3-16
Ran in:
Would be easier to do something along these lines:
This will give you the matrix that you can then strip into indvidual rows if you want
XA = [2 3 1 3 1]; % Set the variables that will make the 'base' matrix
XB = [5 6 7 6 5]; % Set the diagonal values
n = length(XA);
A = repmat(XA,n,1); % Generate the base matrix
B = XB.*eye(n); % Generate diagonals
ix = find(B); % Get indicies of non zero values
A(ix) = B(ix); % Replace diagonal values in A matrix
disp(A)
5 3 1 3 1 2 6 1 3 1 2 3 7 3 1 2 3 1 6 1 2 3 1 3 5

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