How do I code for this random situation?
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On a r*c size grid, 55% of the sites are randomly filled with X, 2% randomly filled with Y, and the rest are empty
3 个评论
John D'Errico
2023-3-20
Geez. WIll you stop changing your questions as fast as you can? I commented on your last question. Then I answered this one, in its previous incarnation, only to see you had comepletely changed the question. I deleted my answer to the last question, and now I'm done.
NAA
2023-3-20
Image Analyst
2023-3-20
@NAA, OK try it this way:
r = 10;
c = 20;
output = nan(r, c);
numX = round(0.55 * r * c) % Number of elements to place an X into.
numY = round(0.02 * r * c) % Number of elements to place a Y into.
X = 1;
Y = 2;
output(1 : numX) = X;
output(numX + 1 : numX + numY) = Y;
randomIndexes = randperm(numel(output));
output = reshape(output(randomIndexes), [r, c])
There are other ways that would work also.
采纳的回答
Image Analyst
2023-3-20
This looks like a homework problem. If you have any questions ask your instructor or read the link below to get started:
Obviously we can't give you the full solution because you're not allowed to turn in our code as your own.
Hint:
output = nan(r, c);
numX = round(0.55 * r * c); % Number of elements to place an X into.
numY = round(0.02 * r * c); % Number of elements to place a Y into.
Two ways to do it:
- You can do it vectorized using randperm (assign the X to the first numX elements, then assign Y to the next numY elements, then use randperm to scramble the order), or
- you can do it brute force using a for loop to place the x value and another loop to place the Y value, but only in the location if the value is a nan (not an X).
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