Finding data in matrice

2 次查看（过去 30 天）
OcDrive
OcDrive 2023-3-27
评论： OcDrive 2023-3-28
Hello
I got a 6x6x365 matrix. 365 refers to days in the year 6x6 are individual values.
I am trying to find a way of writing a loop that would:
  • identify changes in the 6x6 values, BUT - the values have to change by (more or equal to) 24 and the change has to occur in the same place in the matrix AND the day after yesterday (for example there is a value of 50 in a third row, third column, the next day it drops to 20 also in a third row, third column)
  • create another 6x6x365 matrix with the results (I was thinking of a binary matrix - 0 everywhere where there's no change and 1 when the change occurs)
I'm slightly out of ideas on how to approach the problem (especially the same column-same row part and creating a Boolean matrix)
I'm also open to any other ideas of how to sort the data
Any help would be very appreciated, thank you

请先登录，再回答此问题。

采纳的回答

the cyclist
the cyclist 2023-3-27
If M is your data,
bigChange = abs(diff(M,1,3)) >= 24;
  5 个评论
显示 3更早的评论
the cyclist
the cyclist 2023-3-28
You need
[row,col,day]=ind2sub([6,6,364],idx);
instead of
[row,col,day]=ind2sub(size(idx),idx);
OcDrive
OcDrive 2023-3-28
That works great. Thanks so much!

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by