Solving and plotting 2nd order ODE

13 次查看(过去 30 天)
Nina
Nina 2023-4-16
I'm trying to solve the equation y''+sin(y)=0, and plot the results at time 0, 0.1, 0.7, 1.5, 3.0, on a graph.
I tried using this code so far to find the solution, but I am unable to plot the result, '2*atan(exp(C1-t)). I think it's because of the 'C1' in the solution, but I'm not sure how to get rid of it.
>> syms y(t)
>> ode = diff(y,t) == -sin(y)
ode(t) =
diff(y(t), t) == -sin(y(t))
>> ySol(t) = dsolve(ode)
ySol(t) =
2*atan(exp(C1 - t))
0

回答(1 个)

Piotr Balik
Piotr Balik 2023-4-20
编辑:Piotr Balik 2023-4-20
This is constant, whose numerical value is depending on initial conditions.
bnds = y(0) == -0.123
ySol(t) = dsolve(ode, bnds)
But you can also try to solve it substituting to general solution analytically:
Plotting and the example code
syms y(t)
ode = diff(y,t) == -sin(y)
bnds = y(0) == -0.123
ySol(t) = dsolve(ode,bnds)
tv = [0, 0.1, 0.7, 1.5, 3.0];
yv = ySol(tv)
figure,
plot(tv,yv,'o-')

类别

Help CenterFile Exchange 中查找有关 Ordinary Differential Equations 的更多信息

产品


版本

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by