Finding a nonlinear equation root

18 次查看（过去 30 天）
Doga Selcuk
Doga Selcuk 2023-4-17
回答： Torsten 2023-4-17
Hello everyone, i have an equation such that cosh(x)*cos(x)+1=0. I can solve with fsolve but this solver does not give me root, i need to give an interval. How can i solve and finding roots for this equation? Is there any possibilty to solve with using fzero to find roots directly ?In my book roots are:1.875,4.694 and goes on and on
Thanks

请先登录，再回答此问题。

回答（1 个）

Torsten
Torsten 2023-4-17
Ran in:
fun = @(x)cosh(x).*cos(x)+1;
icount = 0;
for i = 1:2:21
x0 = i*pi/2;
icount = icount + 1;
xroot(icount) = fzero(fun,x0);
end
xroot
xroot = 1×11
1.8751 4.6941 7.8548 10.9955 14.1372 17.2788 20.4204 23.5619 26.7035 29.8451 32.9867

类别

在 Help Center 和 File Exchange 中查找有关 Systems of Nonlinear Equations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by