Error: Custom function fitting in MATLAB
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Hey guys, I would like to know why I got this error and how can I fix it. Can I please have your guys comments on this code:
% Load the experimental data and assgin the data to each parameter
data2fit2 = xlsread('data2fit2.xlsx');
ST = data2fit2(:,1);
theta_bar = data2fit2(:,2);
f_exp = data2fit2(:,3);
% Initial Guess
par0 = [0.417257,0.04132,0.001177,0.00961,1.946234];
pars = zeros(size(par0));
% Get the estimate parameters to have best fit to measurement data
par = fminsearch(@(par) err_fcn(pars,...
data2fit2,...
ones(size(data2fit2)),...
@(s,t,p) epsilon_f_of_sigma(s,t,p),...
ST,...
theta_bar),...
par0);
% Use optimized parameters to calculate the estimated epsilon_f by HC model
epsilon_f_modeled = epsilon_f_of_sigma(ST, theta_bar, par);
% Plot fracture criterion
figure;
plot(ST, f_exp, 'o', ST, epsilon_f_modeled, '-')
xlabel('Stress Triaxiality [-]')
% ylabel('Lode Angle Parameter [-]')
ylabel('Equivalent Plastic Strain at Fracture [-]')
function epsilon_f = epsilon_f_of_sigma(ST, theta_bar, pars)
b0 = pars(1);
gamma = pars(2);
c = pars(3);
epsilon_p = 0.0005;
epsilon_0 = 0.0005;
n = pars(4);
a = pars(5);
% Determine strain rate effect on parameter b
if epsilon_p < epsilon_0
b = b0;
else
b = b0*(1 +gamma*log(epsilon_p/epsilon_0));
end
% Define Lode-dependent functions
f1 = (2/3)*cos((pi/6)*(1-theta_bar));
f2 = (2/3)*cos((pi/6)*(3+theta_bar));
f3 = -(2/3)*cos((pi/6)*(1+theta_bar));
% Define each term
Strain_rate_term = b*(1+c).^(1./n);
Lode_dependent_term = ((1/2).*((f1-f2).^a+(f2-f3).^a+(f1-f3).^a)).^(1./a);
Triaxiality_term = c.*(2*ST+f1+f3);
% Final expression for HC model
epsilon_f = Strain_rate_term.* (Lode_dependent_term + Triaxiality_term).^(-1./n);
end
% Define error function
function err = err_fcn(pars,data2fit2,weights4scaling,model_fcn,ST,theta_bar)
model_data = model_fcn(ST,theta_bar,pars);
err = sum((data2fit2(:) - model_data(:)).^2.*weights4scaling);
end
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采纳的回答
Cris LaPierre
2023-4-18
data2fit2(:) and model_data(:) and weights4scaling do not all have the same size.
A = rand(3)
B = rand(2,1)
% Your error
A-B
4 个评论
Cris LaPierre
2023-4-19
No, the new equation does not play a role in obtaining the fit parameters.
Perhaps you are trying to do too much at once. Simplify your code down to just fitting the equation to your data. Get rid of all your extra variables and unnecessary arrays of ones.
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