0 个投票

Suppose,
A=[4 5;4 19;5 7;4 5];
B=[4 5]
if B in A
calculation1;
end
else
calculation2;
end
How Can I code this?

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 采纳的回答

DGM
DGM 2023-4-26
编辑：DGM 2023-4-26
Ran in:

1 个投票

Ran in:
It's not exactly clear what the intended logic is, but this is a simple membership test
A=[4 5; 4 19; 5 7; 4 5];
B=[4 5];
if ismember(B,A,'rows')
% calculation 1;
disp('B is a member of A')
else
% calculation 2;
disp('B is NOT a member of A')
end
B is a member of A

更多回答（1 个）

Juan Ruiz Osorio
Juan Ruiz Osorio 2023-4-26
编辑：Juan Ruiz Osorio 2023-4-26

1 个投票

I think this works if you want to do a calculation for each member of B.
A=[4 5;4 19;5 7;4 5];
B=[4 5];
for i=1:size(B,2)
if ismember(B(i),A)
calculation1;
else
calculation2;
end
end

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