Matlab code errors with histogram generation code

12 次查看(过去 30 天)
This is the coding that I have so far of my code. There aren't any errors with Part A1, and Part A2. I'm only starting to get an error at Part A3 with the histogram line. Most of this code in part 3 is provided by the professor as well.
"Part A: Simulating Probability Distributions"
"Part A1: Write a program that simulates the random varaible Y."
n = 1000
u = rand (1,n)
f_inv = @(x) log(2*(u-2))
X = f_inv(u)
"Part A2: Generate 100,000 random numbers from the distribution of Y"
n= 100,000
u = rand (1,n)
f_inv = @(x) log(2*(u-2))
X = f_inv(u)
"Part A3: Plot the density function"
a = 0;
b = 2.5;
m = 10;
histogram(X,m,"BinLimits",[a b],"Normalization","pdf","FaceColor",[.4 .4 .8])
hold on
f= @(x) (x>0).*log(2*(u-2))
t = linspace (a,b)
plot (t,f(t), "Color",[.2 .2 .6], "LineWidth",3)
The exact code that the professor provided in the handout is below this line of text. All I've done is change the equation in the line f = @(x) to log(2*u-2).
a = 0;
b = 2.5;
m = 10
histogram(X,m,’BinLimits’,[a b], ... ’Normalization’,’pdf’,’FaceColor’,[.4 .4 .8])
hold on
f = @(x) (x>=0).*(k/lambda).*(x/lambda).^(k-1).*exp(-(x/lambda).^k);
t = linspace(a,b); plot(t,f(t),’Color’,[.2 .2 .6],’LineWidth’,3)
These are the three errors that keep coming up no matter what itterations of the code I try.
  1. Error using histogram: Expected input number 1, x, to be real.
  2. Error in histogram>parseinput (line 263): validateattributes(x,{'numeric','logical','datetime','duration','categorical'},...
  3. Error in histogram (line 145): [opts,passthrough,dispatchToCategorical] = parseinput(args,firstaxesinput);
  3 个评论
Tomas
Tomas 2023-5-2
How would I get rid of it? Assuming that my algebra with rearranging natural logs is correct. With the original equation after finding the inverse being -1*log(2-2u)=x.
Rik
Rik 2023-5-2
If you intended to make f_inv depend on the input argument, you need this edit:
f_inv = @(x) log(2*(x-2));
X = f_inv(linspace(0,1,5))
X =
1.3863 + 3.1416i 1.2528 + 3.1416i 1.0986 + 3.1416i 0.9163 + 3.1416i 0.6931 + 3.1416i
As you can see, all values have an imaginary component. You can remove it easily, but it sounds like you should rethink your code instead of blindly removing the component you don't want to have.

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回答(1 个)

VBBV
VBBV 2023-5-2
移动:Image Analyst 2023-5-2
Use real function for f_inv
X = real(f_inv(u))

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