How should i get start with this?

25 次查看（过去 30 天）
Alex Degaga
Alex Degaga 2015-4-1
编辑： Alex Degaga 2015-4-26
The Pythagorean theorem states that a^2 + b^2 = c^2 • Write a MATLAB program in a script file that finds all the combinations of triples a, b, and c that are positive integers all smaller or equal to 50 that satisfy the Pythagorean theorem. Display the results in a three-column table in which every row corresponds to one triple. The first three rows of the table are:
3 4 5
5 12 13
6 8 10
  2 个评论
James Tursa
James Tursa 2015-4-1
Repeated Question:
"The Pythagorean theorem states that a^2 + b^2 = c^2 • Write a MATLAB program in a script file that finds all the combinations of triples a, b, and c that are positive integers all smaller or equal to 50 that satisfy the Pythagorean theorem. Display the results in a three-column table in which every row corresponds to one triple. The first three rows of the table are:
3 4 5
5 12 13
6 8 10
"
Why are you posting this here? You already had a Question for this with Answers:
http://www.mathworks.com/matlabcentral/answers/195511-what-is-the-matlab-program-for-this

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Joep
Joep 2015-4-1
编辑：Joep 2015-4-1
You can start by writing down the Pythagorean therm in matlab. The second is start a loop from 1 to 50. You could use a for loop for that.
n=1;
for a_ = 1:50
for b_ = 1:50
c_=sqrt(a_^2+b_^2);
if c_==round(c_)
if c_<=50
a(n)=a_;
b(n)=b_;
c(n)=c_;
n=n+1;
end
end
clear c_
end
end
Pyth=[a',b',c'];
disp(Pyth)
With this code you have still some double solutions. I let it to you to solve this bug. A solution could be found to let b>a and c>b but I didn't test it, so I could be wrong.
Update: I found by the way this for answer (without the bug):
3 4 5
5 12 13
6 8 10
7 24 25
8 15 17
9 12 15
9 40 41
10 24 26
12 16 20
12 35 37
14 48 50
15 20 25
15 36 39
16 30 34
18 24 30
20 21 29
21 28 35
24 32 40
27 36 45
30 40 50
  2 个评论
Alex Degaga
Alex Degaga 2015-4-2
编辑：Alex Degaga 2015-4-5
Thank you, I had the FOLLOWING, but what you did make sense a lot!
if length(a)==1
if length(b)==1
if length(c)==1
if a==abs(a)
if b==abs(b)
if c==abs(c)
for a=1:1:50
b=1:1:50
c=sqrt(a^2+b^2)
if a<=50&&b<=50&&c<=50
fprintf(' %i %i %i\n', a,b,c)
elseif a>50&&b>50&&c>50
disp('error')
elseif length(a)~=1,length(b)~=1, length(c)~=1
Joep
Joep 2015-4-7
编辑：Joep 2015-4-7
if a<=50&&b<=50&&c<=50
is this necessary? is
if c<=50
not enough? because a en b already are from 1 to 50.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Graphics Object Programming 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by