Why do I get an invalid text character error?

Question

Eric 2023-5-5

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1958659-why-do-i-get-an-invalid-text-character-error

评论： Walter Roberson 2023-5-6

Hello! Here is the code:

V1 = [-3 20 3];
V2 = [3 10 3.5];
V3 = [-123 32 34];
syms vx vy vz real
vslk = [vx ; vy ; vz];
vfl = simplify(norm(vskl));
alfa = acos(vx/vfl);
beta = acos(vy/vfl);
gama = acos(vz/vfl);
for i=1:3
    disp (['vectorul', num2str(i), ':']);
    VX = eval(['V',i]);
    vxn = VX(1);
    vyn = VX(2);
    vzn = VX(3);
    vn=eval(subs(vfl, [vx vy vz], [vxn vyn vzn]));
    disp(['modulul vectorului ', num2str(i), ': ', num2str(vn)]);
    alfan = rad2deg(eval(subs(alfa, [vx vy vz], [vxn vyn vzn])));
    betan = rad2deg(eval(subs(beta, [vx vy vz], [vxn vyn vzn])));
    gaman = rad2deg(eval(subs(gama, [vx vy vz], [vxn vyn vzn])));
    disp(['unghiul alfa al vectorului ', num2str(i), ': ', num2str(alfan), ' grade']);
    disp(['unghiul beta al vectorului ', num2str(i), ': ', num2str(betan), ' grade']);
    disp(['unghiul gama al vectorului ', num2str(i), ': ', num2str(gaman), ' grade']);
end

It gives me the following error:

Error using untitled4

Error: Invalid text character. Check for unsupported symbol, invisible

character, or pasting of non-ASCII characters.

How can I see which line has a problem?

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Answer 1

Walter Roberson 2023-5-5

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https://ww2.mathworks.cn/matlabcentral/answers/1958659-why-do-i-get-an-invalid-text-character-error#answer_1229959

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for i=1:3

i will contain numeric values.

VX = eval(['V',i]);

When you use the [] operator between a character vector and a number, then the result is the same as if you had done

VX = eval(['V',char(i)]);

char(1) does not give you '1' (the character for the digit 1) as a result. char(1) gives you the character whose Unicode Code Point is 1 -- the second Unicode character (first is code point 0). That character is traditionally referred to as SOH, Start of Heading; https://www.compart.com/en/unicode/U+0001

How do you fix this problem? Easy: Don't Use eval.

V1 = [-3 20 3];
V2 = [3 10 3.5];
V3 = [-123 32 34];
Vs = {V1, V2, V3};
for i=1:3
    disp (['vectorul', num2str(i), ':']);
    VX = Vs{i};

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Walter Roberson 2023-5-5

在 MATLAB Online 中打开

There is no documented eval() function for symbolic expressions.

vn=eval(subs(vfl, [vx vy vz], [vxn vyn vzn]));

could do pretty much anything and it would not be a "bug" because the behaviour is not defined by Mathworks.

In practice, eval() of a symbolic expression is treated the same as eval() of char() of the symbolic expression, as if you had written

vn=eval(char(subs(vfl, [vx vy vz], [vxn vyn vzn])));

That might sound reasonable at first, but the problem is that the char() of a symbolic expression is mostly for display purposes, and is not certain to happen to be valid syntax for internal symbolic expressions and is not certain to happen to be valid syntax for MATLAB. There are also some cases where the parameters for symbolic functions are in a different order than the parameters for the similarly-named numeric function; for example historically the parameters for the symbolic function beta were different than the order for the numeric function beta. Using char() produces a human-readable representation, and is not designed to produce something that can be executed numerically.

So, do not use eval() on symbolic expressions. It is undefined, and will give you error messages in some cases, and will silently succeed but give you undesired results in other cases.

Use subs() instead to get down to symbolic numbers, and then double() the symbolic number to get a double precision number.

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Answer 2

Atsushi Ueno 2023-5-5

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You should change the value i to string data.

VX = eval(['V',num2str(i)])

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Walter Roberson 2023-5-6

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To be fair, for this particular operation, selecting one of the V1, V2, V3 variables, that part does not involve any operations on symbolic expressions. The

vn=eval(subs(vfl, [vx vy vz], [vxn vyn vzn]));

is a different part of the code. eval() is being abused in two different ways in the original code.

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