Using string() on double values without automatic rounding?

Hello,
When i use string() with double values, the number is converted to a string where the number is rounded to four decimals, even when there are more decimals in the original double value. Image:
I am currently writing a conversion script where i need the extra decimals. Is it possible to disable this automatic rounding?
Thank you.

 采纳的回答

even when there are more decimals in the original double value
There are no more decimals in the original double value. A double value can only have 15 digits of precision.

3 个评论

I'm not sure im following? If I understand correctly, a double value can have 15 decimal places of precision. Even with numbers with less than 15 digits in total the problem is still there:
Meaning that the string() function rounds to four decimals. My question is wether it is possible to do this double->string conversion without this rounding.
I hope i have made myself more clear, sorry if my initial formulation was off.
You could use num2str,
string( num2str(123.123123123,'%.9f') )
ans = "123.123123123"

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更多回答(1 个)

Rather than slow NUM2STR and then STRING, for a scalar the simpler and more efficient approach is to just call SPRINTF:
sprintf("%.9f",123.123123123)
ans = "123.123123123"
For non-scalar values use COMPOSE:

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