see i am executing the code below

2015 4 7
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更新时间：2015 4 7
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close all;
clear all;
clc;
str=('ttttttPttttPPttt');
length=numel(str);
aa=estring(str)
zz=numel(aa)
comp_ratio=length/zz
------function estring-----------
function y = estring(str)
len = numel(str);
i = 0;
count = zeros(1,len);
y=[];
while( i<len )
j=0;
count(i+1) = 1;
while( true )
j = j + 1;
if( i+j+1 > len )
break;
end
if( str(i+j+1)==str(i+1) )
count(i+1) = count(i+1) + 1;
else
break;
end
end
if( count(i+1)==1 )
a=str(i+1);
length(a);
y = [y a];
i = i + 1;
else
a=str(i+1);
b=count(i+1);
y =[y a num2str(b)];
i = i + b;
end
end
end
I WANT TO KNOW THAT LENGTH/ZZ IS ACTUALLY CALCULATING COMPRESSION RATIO OR MY ASSUMPTION IS WRONG

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Geoff Hayes
Geoff Hayes 2015-4-7

0 个投票

Tina - length is a built-in MATLAB function so please don't use this as a variable name.
As for calculating the data compression ratio, your code seems appropriate. You have divided the uncompressed size by the compressed size which is similar to the same equation found elsewhere.

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