Array indices must be positive integers or logical values.

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Luloah Albanay
Luloah Albanay 2023-5-17
评论： Luca Ferro 2023-5-22
Ran in:
A = [1 2 3; -4 1 2; 0 9 -8];
B = [12; 13; -1];
solution = A\B
solution = 3×1
-1.2424 2.3939 2.8182
det = det(A)
det = -198
Can anyone tell me why i keep getting error?
Array indices must be positive integers or logical values.
det = det(A)

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回答（3 个）

Torsten
Torsten 2023-5-17
编辑：Torsten 2023-5-17
I don't get this error message (see above). But you should rename the result from det(A) - otherwise you have "overwritten" the built-in MATLAB function "det" with the numerical value -198.
  2 个评论
Luloah Albanay
Luloah Albanay 2023-5-17
It used to work before but I am not sure why I keep getting this error now and I did rename it but doesn't seem to work
Steven Lord
Steven Lord 2023-5-17
You will not be able to call the det function while a variable named det is in your workspace. Renaming the variable in your code will not rename the variable that was created in the workspace by a previous run of your code. Change your code, clear the variable, then run the updated code.

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Luca Ferro
Luca Ferro 2023-5-17
You cannot name a variable with the same name as a built-in matlab function.
Change the line det=det(A) to something else like detA=det(A).
  3 个评论
显示 1更早的评论
John D'Errico
John D'Errico 2023-5-17
编辑：John D'Errico 2023-5-17
@Luloah Albanay
If you tried it, and it did not work, then you still have a variable named det in your workspace!
Just changing the line where you created det as a variable will not help, if you will then re-run this script without deleting the variable you just named det.
Luca Ferro
Luca Ferro 2023-5-22
exactly. use this before rerunning the script.
clear det
i would not use clear all since there may be variables you want to keep in the workspace.

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Image Analyst
Image Analyst 2023-5-19
Type
clear all;
to get rid of your "det" that you created previously, and then run your code either in a script or the command window.
clear all;
A = [1 2 3; -4 1 2; 0 9 -8];
B = [12; 13; -1];
solution = A\B
detA = det(A)

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