private variables in a matlab GUI

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Robert
Robert 2023-5-17
回答： Steven Lord 2023-5-17
Hello,
I'm brand new to Matlab, but am knowledable enough to be dangerous as a coder in general. I'm just looking for a best practice here. I've created a GUI to run tests on a benchtop electronics assembly. In the GUI I would like to change settings, pass them to a function and store the results in an array of structures that contain all my test data.
This in the variable I would like to be my array of structures
properties (Access = private)
results;
end
This is what is executed when the user hits the "runTest" button.
% Button pushed function: RunTestButton
function run(app, event)
for x = 1:app.NumberofTestsEditField.Value
app.results(x) = runTest(app.paramX.Value,...
app.paramY.Value,...
app.paramZ.Value,...
)
pause(app.TimeBetweenTestsEditField.Value);
end
end
The error I get is it cannot covert a structure to a double. As stated, I am looking for best practices. runTest does indeed return a structure with some strings, doubles etc. I am presuming it thinks the results variable I defined as a private variable is of type double (I didn't tell it that). Do I just need need to init it as a variable that has the same structure that is being return for runTest()? I don't know how large it is going to be. Appreciate your patience as I am brand new at this :)
Thanks!
Bob

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回答（1 个）

Steven Lord
Steven Lord 2023-5-17
Ran in:
Before you enter the loop, by the way you've defined it the results property of the app is a double array. You can't assign a struct into an element of a double array; MATLAB doesn't know how to perform that conversion.
s = struct('x', 1, 'y', 2, 'z', 3);
x = 1:10;
x(2) = s % error
Conversion to double from struct is not possible.
You could initialize app.results to be a struct either in the definition of the property or as the first line of that method using the struct function.

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