xcorr

2011 10 28
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Hi
Could you please tell me how to understand the delay from the output of the numbers in the below program being displayed? I know the concept of xcorr. I am new to matlab, please help me get through this.
fs=100 t = 0:1/fs:1; x = sin(2*pi*t); y = sin(2*pi*t+pi/10); plot(t,x,t,y) [c, lags] = xcorr(x,y)
Thanks in advance

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Wayne King
Wayne King 2011-10-28

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The frequency of your inputs is 1 Hz, or 2*pi radians per second
The phase lag is pi/10 radians, which corresponds to
pi/10*(1/(2*pi)) seconds. That is 5 sample points at your sampling frequency.
Look at c for c(101:110) which corresponds to lags 0 to 10. See that the maximum value occurs at lag 5, which corresonds to 0.05 seconds as expected.

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