Create a selectable grid in a MATLAB app

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Marina Batlló RIus
回答： Divyanshu 2023-6-16
I am trying to create a MATLB app with APPDesigner. I have added an axis element that has to contain a series of subplots (16x16). I have been able to create the subplots and plot them in the app. However, I wanted to create a grid that separates the subplots, and lets the user select a specific square from the grid to then display their selection in the app. This is what I currently have:
k = 1;
axes_handle = app.SpectralPlotAxes;
figure_spectra = fiu¡gure('Visible', 'off'); % Create a new figure (not visible)
hold on;
figureWidth = 800; % Adjust the figure width as desired
figureHeight = figureWidth; % Set the figure height equal to the width to make it square
set(figure_spectra, 'Units', 'pixels');
set(figure_spectra, 'Position', [100, 100, figureWidth, figureHeight]);
for i = 1:length(FID_data(1,:,1))
for j = 1:length(FID_data(1,1,:))
current_data = FID_data(:, j, i);
subaxis(16,16,k, 'Spacing', 0, 'Padding', 0, 'Margin', 0,'SpacingHoriz', 0);
plot(current_data)
ylim([0 a])
k = k+1;
set(gca, 'XTickLabel', []);
set(gca, 'YTickLabel', []);
set(gca, 'Color','w', 'XColor','b', 'YColor','b')
end
end
frame = getframe(gcf);
spectral_data = frame.cdata;
imshow(imageData,'Parent',axes_handle);
numRows = length(FID_data(1,:,1));
numCols = length(FID_data(1,:,1));
% Determine the size of each grid cell
[height, width, ~] = size(spectral_data);
cellHeight = height / numRows;
cellWidth = width / numCols;
% Prompt the user to select a grid section
[x, y] = ginput(1);
% Calculate the selected grid indices
selectedRow = ceil(y / cellHeight);
selectedCol = ceil(x / cellWidth);
% Display the selected grid indices
app.Label.Text = ['X: ', num2str(selectedRow), ', Y: ', num2str(selectedCol)]
However, when I run this and load my data, instead of creating the grid over the figure I display, the app opens a new figure of the subplots outside the app and does not let me select anything at all. Could anyone help or guide me to solve this problem?
Thank you
  1 个评论
Mario Malic
Mario Malic 2023-5-23
编辑：Mario Malic 2023-5-23
Hey,
try using the CurrentAxes or CurrentObject property from the uifigure object to get the handle to the selected subplot that you can use to display.
https://uk.mathworks.com/help/matlab/ref/matlab.ui.figureappd-properties.html#mw_9947f5f7-275a-4f03-9d2a-88300fecc0b6

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回答（1 个）

Divyanshu
Divyanshu 2023-6-16
Hi Marina,
Here are few points to consider for better understanding of the sample app:
  • I have created a sample app which has four subplots.
  • These subplots I have created using ‘tiledlayout’ function.
  • Initially during the start-up of the app, all the suplots are plotted and corresponding axes to each subplot and the plot itself are hidden.
  • Now the user can specify the subplot number in the edit field, based on the choice corresponding subplot is made visible.
Here is the code-view of the app with example of two subplots, which can be extended further based on use-case:
methods (Access = private)
% Code that executes after component creation
function createPlot(app)
fig = uifigure;
p = uipanel(fig);
t = tiledlayout(p, 2, 2);
x = [1:5];
y = [1,4,6,9,11];
app.ax1 = nexttile(t);
app.p1 = plot(app.ax1,x,y);
app.ax2 = nexttile(t);
app.p2 = plot(app.ax2,2*x,y);
set(app.ax1,'visible','off');
set(app.p1,'visible','off');
set(app.ax2,'visible','off');
set(app.p2,'visible','off');
end
% Button pushed function: SelectButton
function DisplayTile(app, event)
app.SPN = app.SubPlotEditField.Value;
if(app.SPN == 1)
set(app.ax1,'visible','on');
set(app.p1,'visible','on');
set(app.ax2,'visible','off');
set(app.p2,'visible','off');
elseif(app.SPN == 2)
set(app.ax2,'visible','on');
set(app.p2,'visible','on');
set(app.ax1,'visible','off');
set(app.p1,'visible','off');
end
end
end
Please refer the following documentation for further details on ‘tiledlayout’ function:
Create tiled chart layout - MATLAB tiledlayout (mathworks.com)

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