angle of a vector centered at a certain point

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arabe jaradat 2023-5-23

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1971574-angle-of-a-vector-centered-at-a-certain-point

编辑： James Tursa 2023-5-24

I am trying to calulate the hip, knee, ankle joints angles as the image shows

The hip angle is the angle between the "iliac crest marker - hip joint marker" vector extension and the "hip joint marker - knee joint marker" vector. in other words, it draws an x-y plane centered at the hip joint marker and the "iliac crest marker - hip joint marker" vector is its positive y axis, and the hip angle is the angle between the "hip joint marker - knee joint marker" vector and the negative y axis

The knee angle is the angle between the "hip joint marker - knee joint marker" vector extension and the "knee joint marker - ankle joint marker" vector. in other words, it draws an x-y plane centered at the knee joint marker and the "hip joint marker - knee joint marker" vector is its positive y axis, and the knee angle is the angle between the "knee joint marker - ankle joint marker" vector and the negative y axis

the ankle angle is the angle between the "ankle joint marker - toe marker" the positive x axis of an x-y plane that is centered at the ankle joint marker and the "knee joint marker - ankle joint marker" vector is its postive y axis

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James Tursa 2023-5-23

You need to tell us how you have your data points stored. As x-y pairs? In a 2D matrix?

arabe jaradat 2023-5-23

编辑：arabe jaradat 2023-5-23

在 MATLAB Online 中打开

yes as x-y paries

I just have a problem with the equations that calculate the angles

iliac_point = [x_points_sorted(1), y_points_sorted(1)];
hip_point = [x_points_sorted(2), y_points_sorted(2)];
knee_point = [x_points_sorted(3), y_points_sorted(3)];
ankle_point = [x_points_sorted(4), y_points_sorted(4)];
toe_point = [g_center.Centroid(1) g_center.Centroid(2)];
    
hip_vector = [hip_point - iliac_point,0];
knee_vector = [knee_point - hip_point,0];
ankle_vector = [ankle_point - knee_point,0];
toe_vector = [toe_point - ankle_point,0];

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Answer 1

James Tursa 2023-5-23

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1971574-angle-of-a-vector-centered-at-a-certain-point#answer_1243039

Once you have the vectors, you can calculate the angles between the vectors using the technique I posted here:

https://www.mathworks.com/matlabcentral/answers/101590-how-can-i-determine-the-angle-between-two-vectors-in-matlab?s_tid=srchtitle

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arabe jaradat 2023-5-24

I dont want to claculate the angles between the vectors, i want to calculate the angle of each vector with respect to the drawn x -y plane centered at the joints' centers as in the instructions

James Tursa 2023-5-24

编辑：James Tursa 2023-5-24

From your drawing, it looks like the hip and knee joint angles are exactly the angle between vectors, and the ankle joint angle is 90 degrees minus the angle between vectors. Why don't you think your drawn angles are based on the angles between the vectors you created? How else would you calculate these angles if not between the vectors along the lines in your drawing?

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