Reorganizing integer vector preserving order

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Josue Ortega
Josue Ortega 2023-5-25
回答： Jon 2023-5-25
Hi, I have a vector that is a randmperm of n, so it looks like this
x= 2 5 6 13 18 8 14 4 9 3 1 12 16 15 7 11 10 17
Now I have deleteded some entries, based on another different program, in this case 11 and 18, and get the following vector
x'= 2 5 6 13 8 14 4 9 3 1 12 16 15 7 10 17
I want to reorganize x' in such a way that it now becomes a randmperm of 1:size(x'), i.e. that number 12 becomes 11, that number 13 becomes 12, and so on, so that my desired output is
y= 2 5 6 12 8 13 4 9 3 1 11 15 14 7 10 16
Is there an easy way to do this?
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Josue Ortega
Josue Ortega 2023-5-25
also, is there a way to make each element of x that is smaller than p, one unit less than its current value?
say something like x(x<p)=p-1?

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采纳的回答

Jon
Jon 2023-5-25
Ran in:
I think this does what you are asking
xp = [2 5 6 13 8 14 4 9 3 1 12 16 15 7 10 17];
[~,idx] = sort(xp);
xnew(idx) = 1:numel(xp)
xnew = 1×16
2 5 6 12 8 13 4 9 3 1 11 15 14 7 10 16

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