three order complex coefficient polynomial root matlab
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Hi, I would like to find the root for a 3rd order polynomial with complex coefficient.
The polynomial is like:
28x^3 + Ax^2 + Bx - C = 0;
A,B,C are complex numbers.
I appreciate if anyone can help.
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回答(3 个)
Star Strider
2023-5-26
There are at least two options —
z = complex(randn(3,1), randn(3,1))
r = roots([28; z])
syms x
p = 28*x.^3 + z(1,:)*x.^2 + z(2,:)*x + z(3,:);
vpap = vpa(p, 5)
r = vpa(solve(p), 5)
.
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John D'Errico
2023-5-26
Another classic solution is to find the matrix that has the same eigenvalues as your polynomial has roots. Then use eig to compute the eigenvalues of this "companion matrix". This is in fact what roots does.
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Walter Roberson
2023-5-26
syms x A B C
eqn = 28*x^3 + A*x^2 + B*x - C == 0;
solutions = solve(eqn, x, 'MaxDegree', 3)
char(solutions(1))
char(solutions(2))
char(solutions(3))
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