Unable to "read" Text Area

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Larry McDermott
Larry McDermott 2023-5-30
评论： Larry McDermott 2023-5-31
I've got an application that allows a user to enter a lot of information using common Matlab GUI elements such as text boxes, check boxes etc. etc. I've also got some "Text Areas" to allow them to enter more detailed information.
When I try to read it I get error messages and don't see that I'm doing anything wrong, didn't spot anyting obvious in quick search seems like should be a simple one?
My text ares is NotesGeneral:
selection.TypeText(['General Notes: ' app.NotesGeneral.Value]);
This returns:
No method 'TypeText' with matching signature found for class
'Interface.00020975_0000_0000_C000_000000000046'.
I've confrimed name/no typos.
Thanks for any feedback!
  1 个评论
Diwakar Diwakar
Diwakar Diwakar 2023-5-30
It seems like you're trying to use the TypeText method on the selection object. However, the error indicates that this method is not available or does not exist for that object.
Check if the method TypeText is available in the class Interface and Make sure that the class or object you are using supports the TypeText method.
If you provide more context or code snippets surrounding this line, I might be able to assist you further.

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回答（1 个）

Image Analyst
Image Analyst 2023-5-30
Good one: "I've confrimed name/no typos." and "My text ares is..." Ha ha. 🤣
Anyway what is selection and selection.TypeText? And what are you trying to do? Are you trying to construct the string ['General Notes: ' app.NotesGeneral.Value] and put that into another static text label or edit text box? I don't know what those things are but maybe you want to do
app.textLabel.Value = ['General Notes: ', app.NotesGeneral.Value];
where textLabel is the name of the text control that you want to have that string in.
  2 个评论
Larry McDermott
Larry McDermott 2023-5-31
Hah, nice catch....was rushing with my post chasing a train, still should have caught the typo!
I'm trying th grab whatever was typed into the text area and pass it to a word document.
This works great with normal Text Areas but I'm not spotting the syntax (or not available)? to read the text area (benefit is more text). I tried guessing but no joy.
selection.TypeText(['Quality Lead: ' app.QualityEditField.Value]); % Works great, normal text box passed
selection.TypeParagraph; %line break
selection.TypeText(['Supporting Doc path: ' app.DocpathEditField.Value]); % Works great, normal text box
selection.TypeParagraph; %line break
selection.TypeText(['General Notes: ' app.NotesGeneral.Value]); % Does not work with Text Area
selection.TypeParagraph; %line break
Thanks for any suggestions!
Larry McDermott
Larry McDermott 2023-5-31
OK, I found something that was very helpful. The text area is a cell array so I can read it, for example"
selection.TypeText(['General Notes: ' app.NotesGeneral.Value{1}]); % Reads first line!
Thanks for the suggestions!

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