How to flip an ordered X-axis that is half half separated for data?
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Hi, I have a plot that I want its X-axis to be reversed. My data on X-axis is showing as
[1 2 3 4 5 6 7 8 9 10 11 12] I want to reverse it in a way that it represents [6 5 4 3 2 1 12 11 10 9 8 7] (reversing it from the middle for two seperate parts). How is it possible? I tried set(gca, 'XDir','reverse') but it reverses it to [12 11 10 9 8 7 6 5 4 3 2 1]. I cannot share the code or data due to confidentiality. Thanks in advance.
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Dorna
2023-6-4
1 个评论
Star Strider
2023-6-4
编辑:Star Strider
2023-6-4
O.K.
That seems to be essentially what I wrote, although in one column not five. You can use my approach to plot it.
更多回答(2 个)
VBBV
2023-6-3
Use xticklabels function to modify the order of axis labels
x1 = {'6','5','4','3','2','1'};
x2 ={'12','11','10','9','8','7'};
plot(rand(1,12))
xticks(1:12)
xticklabels([x1,x2])
2 个评论
VBBV
2023-6-3
编辑:VBBV
2023-6-3
can you explain why you DONT want to actually work with plot data but still want to flip ordered x-axis values ?
v = [16 5 9 4 2 11 7 14];
v2 = v([5:8 1:4]) % Extract and swap the halves of v
% flip the values for vector v
v2 = flip(v)
% another way
v2 = v([8:-1:5 , 4:-1:1])
How can I make the V2 to be [14 7 11 2 4 9 5 16], can I use prime on 5:8'?
You can use the flip function to get the desired result as shown above
Star Strider
2023-6-3
One approach that changes the x-axis and the data —
xv = [1 2 3 4 5 6 7 8 9 10 11 12]; % Independent Variable
yv = (xv/max(xv)).^2; % Dependent Variable
xvi = [6 5 4 3 2 1 12 11 10 9 8 7]; % Indexing Vector
figure
plot(xv, yv)
grid
xticks(xv)
title('Original')
Vectors = [xv(xvi); yv(xvi)]
figure
plot(xv, yv(xvi))
grid
xticks(xv)
xticklabels(xv(xvi))
title('Reversed & Concatenated')
It may be challenging to elliminate the connecting line between 1 and 12 here. If necessary, that would require putting a NaN value at the beginning or end of the ‘xv’ and ‘yv’ vectors, and adjusting ‘xvi’ accordingly.
.
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