At the beginnnig looks like weird
>> x=0.23: 0<x<1
This does not ask the question "Is x between 0 and 1 exclusive?" It is instead interpreted as:
x = 0.23;
y = (0 < x) < 1
The first part of the expression for y, (0 < x), returns either false (treated as 0) or true (treated as 1) depending on the value you specified for x. In this case since 0 is less than 0.23, it is true. So y becomes:
y = true < 1
Since true is treated as 1 and 1 is not less than 1, y is false.
Your second expression, x=0.23: 0.1<x<1.1, will always return true. Both false (0) and true (1) are strictly less than 1.1 so it doesn't matter whether 0.1 is less than x or not.
x = 0.23;
z = 0.1<x<1.1
z = (0.1 < x) < 1.1
z = true < 1.1
x = Inf;
z = 0.1<x<1.1
If you enter this in the Editor, Code Analyzer should warn about that pattern and suggest the approach others have already recommended earlier, using two separate tests combined using the & or && operators.
x = 2;
z = (0.1 < x) & (x < 1.1)
