Silly question about 2 column matrix

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A Poyser
A Poyser 2023-6-6
评论： John D'Errico 2023-6-6
Ran in:
It is my understanding that
a = [1 3 5; 2 4 6; 7 8 10]
a = 3×3
1 3 5 2 4 6 7 8 10
yet
AL01-SIGMA09 = [1183.885678 512.1;
Incorrect use of '=' operator. Assign a value to a variable using '=' and compare values for equality using '=='.

Error in connector.internal.fevalMatlab

Error in connector.internal.fevalJSON
568.8329716 512.1;
417.7853247 512.1;
200.7327245 512.1;
38.95699064 512.1;
19.83313269 512.1;
14.56665171 512.1;
8.010756815 512.1]
gives me this error, I can't see the difference. Can someone explain how I create a two column matrix from this data.
Thanks in advance
Alex

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采纳的回答

Tushar
Tushar 2023-6-6
Ran in:
Hello A Poyser,
Please note that the error you are getting is not due to the "=" or "==" operator but it is simply because you cannot use hyphens in variable naming in MATLAB. Change the variable name and you can create the matrix using the very same syntax you provided :) Instead try using underscore.
AL01_SIGMA09 = [1183.885678 512.1;
568.8329716 512.1;
417.7853247 512.1;
200.7327245 512.1;
38.95699064 512.1;
19.83313269 512.1;
14.56665171 512.1;
8.010756815 512.1]
AL01_SIGMA09 = 8×2
1.0e+03 * 1.1839 0.5121 0.5688 0.5121 0.4178 0.5121 0.2007 0.5121 0.0390 0.5121 0.0198 0.5121 0.0146 0.5121 0.0080 0.5121
  2 个评论
A Poyser
A Poyser 2023-6-6
Tushar, yes I realised as soon as I saw the answer from VBBV. Thanks for the help.
John D'Errico
John D'Errico 2023-6-6
In fact, really this answer gets to the correct point of the problem best. Sadly, it was not accepted as the correct answer. That is a flaw of Answers. But at least I can give it an up-vote. Such is life.

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更多回答（1 个）

VBBV
VBBV 2023-6-6
编辑：VBBV 2023-6-6
Ran in:
From the below error, its visible that AL01 & SIGMA09 are both scalar variables and difference between them is also scalar. They have different dimensions when compared with matrix present in RHS & not possible to equate them
AL01 = 3;
SIGMA09 = 2;
AL01-SIGMA09 = [1183.885678 512.1;
Incorrect use of '=' operator. Assign a value to a variable using '=' and compare values for equality using '=='.
568.8329716 512.1;
417.7853247 512.1;
200.7327245 512.1;
38.95699064 512.1;
19.83313269 512.1;
14.56665171 512.1;
8.010756815 512.1]
  1 个评论
A Poyser
A Poyser 2023-6-6
Ahhhhh. Silly me. It is a naming error. It's one array AL01-SIGMA09 should be AL01_SIGMA09.
Thanks so much.

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