if loop to find values in a variable

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C.G.
C.G. 2023-6-8
编辑： Matt J 2023-6-8
I have 2 arrays of numbers, t and Q. I want to use an if loop to do the following:
  • find if tfind is present in the variable t.
  • if this number is present, find the index of the number within this array.
  • find the number in the variable Q which corresponds to this index
my code runs, but the variable c is empty. Can anybody help?
t = [4 5 7 8 10 11 12 15 17 20 22 24 26 27 28];
Q = [1 3 4 1 5 8 4 2 6 1 4 2 8 3 5];
p = 10;
np = 3;
for i = 1:p
c = [];
for j = 1:np
tfind = (j-1)*p+i
if ismember(t, tfind) %find if tfind is in t
loc = find(t=tfind) % find the index of tfind within t
q = Q(loc) %find the number in Q which corresponds to this index
end
c = [c;q] %assign the values of q to new variable
end
end

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回答（1 个）

Matt J
Matt J 2023-6-8
编辑：Matt J 2023-6-8
Ran in:
One possibility
t = [4 5 7 8 10 11 12 15 17 20 22 24 26 27 28];
Q = [1 3 4 1 5 8 4 2 6 1 4 2 8 3 5];
p = 10;
np = 3;
c = cell(1,p*np); k=0;
for i = 1:p
for j = 1:np
tfind = (j-1)*p+i;
k=k+1;
c{k}=Q(t==tfind);
end
end
c=cell2mat(c)
c = 1×15
8 4 4 1 2 3 2 8 4 6 3 1 5 5 1
  2 个评论
C.G.
C.G. 2023-6-8
编辑：Matt J 2023-6-8
Ran in:
Thank you for your response.
Your answer didnt quite answer my question but got me closer to it.
What I want it to do, is to loop through and save each iteration of c_s rather than just the last one. I want to end up with 3 rows of data that I can take a mean from. Do you know how I can do this?
t = [4 5 7 8 10 11 12 15 17 20 22 24 26 27 28];
Q = [1 3 4 1 5 8 4 2 6 1 4 2 8 3 5];
p = 10;
Lti = 30;
np = Lti/p;
c = []; %ensemble average signal
for i = 1:p
c_s = []; %sediment flux values equal to each second of the period
for j = 1:np
tfind = (j-1)*p+i;
c_s = Q(t==tfind);
end
c = [c;mean(c_s)];
end
c
c = 10×1
NaN 4 NaN 2 NaN 8 3 5 NaN NaN
Matt J
Matt J 2023-6-8
编辑：Matt J 2023-6-8
Ran in:
I want to end up with 3 rows of data that I can take a mean from.
So, c is meant to have np=3 rows? How many columns?
Maybe this is what you mean:
t = [4 5 7 8 10 11 12 15 17 20 22 24 26 27 28];
Q = [1 3 4 1 5 8 4 2 6 1 4 2 8 3 5];
p = 10;
Lti = 30;
np = Lti/p;
c = nan(np,1); %ensemble average signal
for j = 1:np
for i = 1:p
tfind = (j-1)*p+i;
c(j) = mean( Q(t==tfind) );
end
end
c %three rows
c = 3×1
5 1 NaN

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