rotate polar angle by an arbitrary angle

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Jingtao 2023-6-10

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1981174-rotate-polar-angle-by-an-arbitrary-angle

评论： Jingtao 2023-6-10

采纳的回答： Matt J

在 MATLAB Online 中打开

I got a polar angle map THETA0 from running the snippet below.

N = 1024;  
x0 = linspace(-N/2, N/2, N); 
y0 = x0;
[X0,Y0] = meshgrid(x0,y0);
[THETA0,R0] = cart2pol(X0,Y0);

But cart2pol returns polar angle map starting from the positive x-axis. I want to get a polar angle map starting at an arbitrary angle of beta. How can I realize this?

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采纳的回答

Matt J 2023-6-10

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https://ww2.mathworks.cn/matlabcentral/answers/1981174-rotate-polar-angle-by-an-arbitrary-angle#answer_1253614

在 MATLAB Online 中打开

THETA0=THETA0-beta;

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Jingtao 2023-6-10

Thanks! THETA0=mod(THETA0-beta,2*pi) works right!

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