Extract column from text file

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Suuz HMS
Suuz HMS 2023-6-12
评论： Suuz HMS 2023-6-13
Hi, for my research project I have to analyze a certain output. The output gives a lot of measurements (also a lot of data I don't need), but I don't know how to extract the specific column of data that I do need. The data looks like this:
P1,R0,14:17:36.779,47,0.01421266,[-0.03077913; 0.3226232; -0.4286367],[0; 0; 0],[-0.4424625; 0.120887; -0.9627059],[-0.03836464; 0.5967162; 0.3170188],[-6.699989; -7.350024; 5.199996],50.48101,0.7456555,0,0,0,-5.2,0
P0,R0,14:17:36.823,47,0.01403595,[-0.03077913; 0.3226232; -0.4286367],[0; 0; 0],[-0.4424625; 0.120887; -0.9627059],[-0.03836464; 0.5967162; 0.3170188],[-6.699989; -7.350024; 5.199996],50.48101,0.7456555,0.08738,0.6293842,17.97661,-5.2,0
But I only need the first number between brackets (value -0.03077913 here). How do I do this?
  2 个评论
the cyclist
the cyclist 2023-6-12
The best method will depend on exactly what format of file you have. (For example, is it Excel, a CSV, etc.?) Can you upload the file (using the paper clip icon from the INSERT area of the toolbar), or at least a few representative lines?
Suuz HMS
Suuz HMS 2023-6-13
The file gets downloaded as a txt-file, but can also be saved as a .m file.

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回答（2 个）

Kautuk Raj
Kautuk Raj 2023-6-13
To extract the first number between the brackets in the data provided, we can use regular expressions in MATLAB.
This regular expression pattern \[([-0-9\.]+);([-0-9\.]+);([-0-9\.]+)\] will match the three numbers between the brackets and captures them in separate groups.
Stephen23
Stephen23 2023-6-13
Ran in:
Fake data (you would use FILEREAD):
S = sprintf('%s\n','P1,R0,14:17:36.779,47,0.01421266,[-0.03077913; 0.3226232; -0.4286367],[0; 0; 0],[-0.4424625; 0.120887; -0.9627059],[-0.03836464; 0.5967162; 0.3170188],[-6.699989; -7.350024; 5.199996],50.48101,0.7456555,0,0,0,-5.2,0','P0,R0,14:17:36.823,47,0.01403595,[-0.03077913; 0.3226232; -0.4286367],[0; 0; 0],[-0.4424625; 0.120887; -0.9627059],[-0.03836464; 0.5967162; 0.3170188],[-6.699989; -7.350024; 5.199996],50.48101,0.7456555,0.08738,0.6293842,17.97661,-5.2,0')
S =
'P1,R0,14:17:36.779,47,0.01421266,[-0.03077913; 0.3226232; -0.4286367],[0; 0; 0],[-0.4424625; 0.120887; -0.9627059],[-0.03836464; 0.5967162; 0.3170188],[-6.699989; -7.350024; 5.199996],50.48101,0.7456555,0,0,0,-5.2,0 P0,R0,14:17:36.823,47,0.01403595,[-0.03077913; 0.3226232; -0.4286367],[0; 0; 0],[-0.4424625; 0.120887; -0.9627059],[-0.03836464; 0.5967162; 0.3170188],[-6.699989; -7.350024; 5.199996],50.48101,0.7456555,0.08738,0.6293842,17.97661,-5.2,0 '
C = regexp(S,'(?<=\[)(-|+)?\d+\.?\d*','match')
C = 1×10 cell array
{'-0.03077913'} {'0'} {'-0.4424625'} {'-0.03836464'} {'-6.699989'} {'-0.03077913'} {'0'} {'-0.4424625'} {'-0.03836464'} {'-6.699989'}
V = str2double(C)
V = 1×10
-0.0308 0 -0.4425 -0.0384 -6.7000 -0.0308 0 -0.4425 -0.0384 -6.7000

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