Make a new variable based on data in the cell array.
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I have a cell array called C. Each row in C has a different set of integerS stored as a cell
I wan to write a code such that it looks in each row/cell of C, if any integer in the row is equal to 1, it stores in the new variable x, the cell number.
I have the code:
x = [];
for i = 1:numel(C)
if any(C{i}==1)
x(i) = i; %store index of that cell %i know this line is the problem
end
end
problem is this creates length of x same as length of C with zeros in between. I dont want those zeros, instead just a vector of indices where a cell of C has the value 1.
for example right now, the out put is :
1 2 3 0 0 6
where as I want something like this:
1 2 3 6
采纳的回答
x=[1 2 3 0 0 6]
x=nonzeros(x)'
更多回答（2 个）
x=[1 2 3 0 0 6]
x=x(x~=0)
x=[1 2 3 0 0 6]
x=x(logical(x))
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