Make a new variable based on data in the cell array.

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Saim Ehtesham
Saim Ehtesham 2023-6-13
评论： Saim Ehtesham 2023-6-13
I have a cell array called C. Each row in C has a different set of integerS stored as a cell
I wan to write a code such that it looks in each row/cell of C, if any integer in the row is equal to 1, it stores in the new variable x, the cell number.
I have the code:
x = [];
for i = 1:numel(C)
if any(C{i}==1)
x(i) = i; %store index of that cell %i know this line is the problem
end
end
problem is this creates length of x same as length of C with zeros in between. I dont want those zeros, instead just a vector of indices where a cell of C has the value 1.
for example right now, the out put is :
1 2 3 0 0 6
where as I want something like this:
1 2 3 6

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采纳的回答

Matt J
Matt J 2023-6-13
编辑：Matt J 2023-6-13
Ran in:
x=[1 2 3 0 0 6]
x = 1×6
1 2 3 0 0 6
x=nonzeros(x)'
x = 1×4
1 2 3 6

更多回答（2 个）

Matt J
Matt J 2023-6-13
编辑：Matt J 2023-6-13
Ran in:
x=[1 2 3 0 0 6]
x = 1×6
1 2 3 0 0 6
x=x(x~=0)
x = 1×4
1 2 3 6
Matt J
Matt J 2023-6-13
Ran in:
x=[1 2 3 0 0 6]
x = 1×6
1 2 3 0 0 6
x=x(logical(x))
x = 1×4
1 2 3 6

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