Low pass filter for image

I want to create a lowpass filter (circle!) for an 110 x 160 pixel image.
The cut-off frequency should be 0.13/pixel.
What I tried so far:
bricks = im2double(imread("bricks.jpg"));
y1 = fft2(bricks);
[N, M] = size(bricks);
u = -1/2:1/M:1/2-1/M;
v = -1/2:1/N:1/2-1/N;
[U, V] = meshgrid(u, v);
d = U.*U/(0.13*0.13) + V.*V/(0.13*0.13);
mask = d <= 1;
yt1 = fftshift(y1);
yt1 = yt1.*mask;
low_filtered_image = ifft2(ifftshift(yt1), 'symmetric');
The spectrum of my filter and the filtered spectrum look like this:
That gives me the following result for my lowpass filtered image:
But I am not sure if this is correct.

回答(1 个)

Image Analyst
Image Analyst 2023-6-24

1 个投票

Use fft2, then zero out anything beyond 0.13. I'll leave it to you to figure out what index that is in the spectral image.
This looks like a homework problem. If you have any questions ask your instructor or read the link below to get started:
Obviously we can't give you the full solution because you're not allowed to turn in our code as your own.

4 个评论

But the return value of fft2 is not the frequency. So how can I compare the return value to a frequency?
The return value of fft2 is the frequency image. Read up on it.
I know that this is the frequency image. Anyway, I found this post https://stackoverflow.com/questions/64036198/matlab-how-to-apply-low-pass-and-high-pass-filters-using-fft2-and-fftshift . But this does not solve my problem because 0.13 is too low.
Then use a higher value so that less of the spectral image is erased. See attached demos.

请先登录,再进行评论。

类别

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by