FFT - How to transform my amplitudes into dB

354 次查看(过去 30 天)
Hello,
I have done a code to obtain the FFT of an audio recorded with Matlab. I'm getting my result in amplitude but I'd like to get it in dB in the frequency domain... Could someone please help me?
Here is my code and my curves:
Thank you for your help.

回答(1 个)

Diya Tulshan
Diya Tulshan 2023-6-26
Hii Jacques,
I understand you want to plot the data in db.
Kindly look into the code given below, it should solve your problem:-
Fs = 16000; % Sampling rate (Hz)
Channels = 1; % Number of audio channels
bits = 16; % Number of bits per sample
r = audiorecorder(Fs, bits, Channels);
duration = 10;
disp('Recording started');
recordblocking(r, duration);
disp('Recording stopped');
X = getaudiodata(r);
N = length(X);
f = (0:N/2) * (Fs/N);
t = (0:N-1) / Fs;
subplot(2,1,1);
plot(t, X);
xlabel('Time (s)');
ylabel('Amplitude');
title('Time Domain Plot');
Y = fft(X, N);
Y = abs(Y(1:N/2+1));
fftResult_dB = 20 * log10(Y); % covert into dB
subplot(2,1,2);
plot(f, fftResult_dB);
xlabel('Frequency (Hz)');
ylabel('Amplitude (dB)');
title('Frequency Domain Plot');
xlim([0, Fs/2]);
grid on;
Hope this helps!
  2 个评论
Jacques
Jacques 2023-6-26
Thank you Diya for your help!
I've tested your code and this is what I get:
Getting negative values for my dBs disturbs me...I don't know how to interpret them
Paul
Paul 2023-6-26
编辑:Paul 2023-6-26
Converting any number less than 1 and greater than 0 to dB will yield a negative result. db(0) is -Inf.
20*log10([2 1 .5 .1 0])
ans = 1×5
6.0206 0 -6.0206 -20.0000 -Inf
So the negative values in dB tells you that the corresponding absolute amplitude is in the range 0 < amplitude < 1.

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