App designer - problem implementing filter based on tree nodes

Question

Teshan Rezel 2023-6-27

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1988783-app-designer-problem-implementing-filter-based-on-tree-nodes

评论： Teshan Rezel 2023-7-10

采纳的回答： Kevin Holly

在 MATLAB Online 中打开

Hi folks,

i have a tree that looks something like this:

I am trying to createn a filter based on "cause" whereby you can see things on a table to the left based on one or more of the selected criteria (such as fire, or fire + attack).

So I've used the following code from another thread (below). However, I am getting the error "Unrecognized method, property, or field 'Cause' for class 'matlab.ui.control.Table'. Is there a way around this please?

        function [filter_criteria, checked_nodes] = get_checked_nodes(~, checked)
            % checked = checked nodes object from tree
            % if tr = tree, checked=tr.CheckedNodes
            % filter_criteria = structure with variables and values objects,
            % each record has the name of the variable in variables as a string and a string array of the values for those items checked in the nodes.
            % checked_nodes = table with all checked nodes. Table Structure includes node level (only level 2 is included), 
            % Parent  (variable name), and leaf (selected string option in tree).
            % If the parent node is checked, the values will not be returned, because all records would be returned and there are no criteria to filter on. 
            
            if size(checked,1)==0
                filter_criteria=[];
                checked_nodes=[];
                return
            end
            
            node_num=size(checked,1);
            checked_nodes=table(Size=[ node_num 3],VariableTypes=["double" "string" "string"],VariableNames=["node_level" "parent_node" "leaf"]);
            
            for node_id=1:node_num
               if checked(node_id).Parent.Type~="uitreenode" % if parent node is not uitreenode, then top level
                   checked_nodes.node_level(node_id)=1;
                   checked_nodes.parent_node(node_id)=checked(node_id).Text; % parent nodes have themselves as parent here
                   checked_nodes.leaf(node_id)=checked(node_id).Text;
               else
                   checked_nodes.node_level(node_id)=2;
                   checked_nodes.parent_node(node_id)=checked(node_id).Parent.Text;
                   checked_nodes.leaf(node_id)=checked(node_id).Text;
               end
            end
            
            check_parents=checked_nodes.leaf(checked_nodes.node_level==1);
            node_rows=~ismember(checked_nodes.parent_node,check_parents); 
            checked_nodes=checked_nodes(node_rows,:); % removes parents from checked_nodes
            
            clear filter_criteria
            varnames=unique(checked_nodes.parent_node);
            for varnum=1:size(varnames,1)
                filter_criteria(varnum).variables=varnames(varnum);
                filter_criteria(varnum).values=checked_nodes.leaf(checked_nodes.parent_node==varnames(varnum))';
            end
        end
        
                function [filtered_rows] = get_filtered_rows(~,source_table, filter_criteria)
            % create a logical array of filtered rows based upon a source table and filter criteria. 
            % The array can then be used to select specific rows from a table or array. 
            % The filter criteria selects fields that have any option in the values within a field, 
            % but if multiple fields are used, the row must be selected for each variable used in the filter.
            if isempty(filter_criteria)
                filtered_rows=true(size(source_table,1),1);
                return;
            end
            num_vars=size(filter_criteria,2);
            filtered_matrix=[];
            for varnum=1:num_vars
                filtered_matrix(:,varnum)=ismember(source_table.(filter_criteria(varnum).variables),filter_criteria(varnum).values);
            end
            filtered_rows=all(filtered_matrix,2);
        end
        

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Answer 1

Kevin Holly 2023-6-27

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1988783-app-designer-problem-implementing-filter-based-on-tree-nodes#answer_1263678

FilteringTableDatawithNodeApp.mlapp

Teshan,

I created an app based on the scripts provided (see attached). Please let me know if this answers your question. I believe you were inputing the incorrect variable as the source_table into the get_filtered_rows function.