How select/crop geographic region on the basis of lat/lon values?

2 次查看(过去 30 天)
I want to select/crop region on the basis of lat/lon.
I have geographical data with dimensions of lat,lon and time from which I want to crop a region using four lat/lon(e.g. LAT: 13,18; LON: 73,76) points like a rectangle.
I have attached my sample data for reference.
Can anyone help me with this problem?

采纳的回答

Pranavkumar Mallela
编辑:Pranavkumar Mallela 2023-7-27
Hi,
As per my understanding, you are trying to crop a region that is part of the sample data, which includes the 'rf' value over a 100x100 area and 48 time instances.
First use 'ncread' to read the 'rf' variable from the above attached file in the following way:
rf = ncread("test.nc", 'rf');
The variable 'rf' is a 100x100x48 double matrix. To crop a certain geographical region at a given time 't', you can use the following code:
cropped_region = rf(13:18, 73:76, t); % at a given time 't'
For more information regarding selection of data from a matrix, you can refer the following documentation: https://www.mathworks.com/help/matlab/math/array-indexing.html
Hope this helps! Thanks!
  3 个评论
Pranavkumar Mallela
编辑:Pranavkumar Mallela 2023-7-27
Hey, thanks for clarifying that.
You can utilize the 'find' function to find the indices of the required latitude and longitude ranges.
The code is as follows:
lat = [1 2 3 4 5 6 7 8 9 10]; % assume this is your latitude data
lon = [1 2 3 4 5 6 7 8 9 10]; % assume this is your longitude data
% Set the required limits here
req_lat_ll = 13; req_lat_ul = 18;
req_lon_ll = 73; req_lon_ul = 76;
lat_ll = find(lat <= req_lat_ll ,1,'last'); % ll = lower limit
lat_ul = find(lat >= req_lat_ul,1,'first'); % ul = upper limit
lon_ll = find(lon <= req_lon_ll ,1,'last');
lon_ul = find(lon >= req_lon_ul,1,'first');
cropped_region = rf(lat_ll:lat_ul, lon_ll:lon_ul, t); % at a given time 't'
Now you should be able to access rainfall using latitude and longitude ranges.
For more information regarding the 'find' function, please refer to this documentation:
Thanks! Hope this helps!

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Earth, Ocean, and Atmospheric Sciences 的更多信息

产品


版本

R2023a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by