Need an Elegant Sorting Solution for Directory File Names

Question

John Cruce 2023-7-9

0
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https://ww2.mathworks.cn/matlabcentral/answers/1993708-need-an-elegant-sorting-solution-for-directory-file-names

编辑： Voss 2023-7-9

采纳的回答： Voss

I have a directory of filenames, (within a files structure array) structured like this:

cdef2.20140101.pdef.txt

cdef2.20140102.pdef.txt

....

pdef.gdef.201300101-20130105.txt

pdef.gdef.201300106-20130110.txt

....

I need to reorder these (ascending order from oldest to newest) according to the dates embedded within these file names which are formatted like YYYYMMDD. I've explored several options, but I'm seeking an elegant solution without do loops. Any tips or suggestions would be appreciated.

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John Cruce 2023-7-9

Needing to sort by the first date in pdef.gdef.201300101-20130105.txt (i.e., 20130101). I considered running a shell script to rename the files but trying not to add another step.

Sandeep Mishra 2023-7-9

Can we assume that there exist only two type of files?

One which starts with cdef2 and one which starts with pdef?

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Answer 1

Voss 2023-7-9

1
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https://ww2.mathworks.cn/matlabcentral/answers/1993708-need-an-elegant-sorting-solution-for-directory-file-names#answer_1269998

编辑：Voss 2023-7-9

在 MATLAB Online 中打开

filenames = { ...
    'cdef2.20140101.pdef.txt'; ...
    'cdef2.20140102.pdef.txt'; ...
    'pdef.gdef.20130101-20130105.txt'; ...
    'pdef.gdef.20130106-20130110.txt'}
filenames = 4×1 cell array
    {'cdef2.20140101.pdef.txt'        }
    {'cdef2.20140102.pdef.txt'        }
    {'pdef.gdef.20130101-20130105.txt'}
    {'pdef.gdef.20130106-20130110.txt'}
dates = regexp(filenames,'\d{8}','match','once');
[~,idx] = sort(dates);
sorted_filenames = filenames(idx)
sorted_filenames = 4×1 cell array
    {'pdef.gdef.20130101-20130105.txt'}
    {'pdef.gdef.20130106-20130110.txt'}
    {'cdef2.20140101.pdef.txt'        }
    {'cdef2.20140102.pdef.txt'        }