Need an Elegant Sorting Solution for Directory File Names

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John Cruce
John Cruce 2023-7-9
编辑： Voss 2023-7-9
I have a directory of filenames, (within a files structure array) structured like this:
cdef2.20140101.pdef.txt
cdef2.20140102.pdef.txt
....
pdef.gdef.201300101-20130105.txt
pdef.gdef.201300106-20130110.txt
....
I need to reorder these (ascending order from oldest to newest) according to the dates embedded within these file names which are formatted like YYYYMMDD. I've explored several options, but I'm seeking an elegant solution without do loops. Any tips or suggestions would be appreciated.
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John Cruce
John Cruce 2023-7-9
Needing to sort by the first date in pdef.gdef.201300101-20130105.txt (i.e., 20130101). I considered running a shell script to rename the files but trying not to add another step.
Sandeep Mishra
Sandeep Mishra 2023-7-9
Can we assume that there exist only two type of files?
One which starts with cdef2 and one which starts with pdef?

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Voss
Voss 2023-7-9
编辑：Voss 2023-7-9
Ran in:
filenames = { ...
'cdef2.20140101.pdef.txt'; ...
'cdef2.20140102.pdef.txt'; ...
'pdef.gdef.20130101-20130105.txt'; ...
'pdef.gdef.20130106-20130110.txt'}
filenames = 4×1 cell array
{'cdef2.20140101.pdef.txt' } {'cdef2.20140102.pdef.txt' } {'pdef.gdef.20130101-20130105.txt'} {'pdef.gdef.20130106-20130110.txt'}
dates = regexp(filenames,'\d{8}','match','once');
[~,idx] = sort(dates);
sorted_filenames = filenames(idx)
sorted_filenames = 4×1 cell array
{'pdef.gdef.20130101-20130105.txt'} {'pdef.gdef.20130106-20130110.txt'} {'cdef2.20140101.pdef.txt' } {'cdef2.20140102.pdef.txt' }

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