Is there a way to use findgroups() so that it is based on order in the matrix instead of alphabetical?

Question

Liam 2023-7-13

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https://ww2.mathworks.cn/matlabcentral/answers/1995708-is-there-a-way-to-use-findgroups-so-that-it-is-based-on-order-in-the-matrix-instead-of-alphabetica

评论： Star Strider 2023-7-13

I am using findgroups() as an integral part of the script I'm currently working with, but the way that findgroups() outputs its groups is causing issues.

x = {'m1' 'n1' 'k1' 'k1' 'p1' 'p1' 'b1' 'b1' 'b1'}
x = 1×9 cell array
    {'m1'}    {'n1'}    {'k1'}    {'k1'}    {'p1'}    {'p1'}    {'b1'}    {'b1'}    {'b1'}
[g,g_id] = findgroups(x)
g = 1×9
     3     4     2     2     5     5     1     1     1
g_id = 1×5 cell array
    {'b1'}    {'k1'}    {'m1'}    {'n1'}    {'p1'}

What I would prefer is if g outputted as [1 2 3 3 4 4 5 5 5] and g_id as {'m1' 'n1' 'k1' 'p1' 'b1'}. Is there any way to do this?

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Answer 1

Star Strider 2023-7-13

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There doesn’t appear to be that option for findgroups. If you only have one vector, the unique function can do thaat using the 'stable' setOrder —

x = {'m1' 'n1' 'k1' 'k1' 'p1' 'p1' 'b1' 'b1' 'b1'}
x = 1×9 cell array
    {'m1'}    {'n1'}    {'k1'}    {'k1'}    {'p1'}    {'p1'}    {'b1'}    {'b1'}    {'b1'}
[g,~,g_id] = unique(x,'stable')
g = 1×5 cell array
    {'m1'}    {'n1'}    {'k1'}    {'p1'}    {'b1'}
g_id = 9×1
     1
     2
     3
     3
     4
     4
     5
     5
     5