Histogram normalisation: a question about terminology

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Sim 2023-7-14

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评论： Sim 2023-8-1

Let's consider the histogram and histcounts functions, as in these two cases:

num_bins = 30; % <-- note: I specify the "number of bins" and not the "bin width", which can be different from 1
% Case 1
histcounts(X,num_bins,'Normalization','probability'); 
histogram(X,'NumBins',num_bins,'Normalization','probability');
% Case 2
histcounts(X,num_bins,'Normalization','pdf'); 
histogram(X,'NumBins',num_bins,'Normalization','pdf');

Do I understand correctly that

For Case 1, I get the "Relative Frequency Histogram" or an "empirical estimate of the Probability Mass Function"?
For Case 2, - where I divide by the bin widths as well -, I get the an "empirical estimate of the Probability Density Function"?

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Sim 2023-8-1

@MathWorks Support Team...?

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回答（1 个）

Satwik Samayamantry 2023-7-14

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Hi Sim,

Yeah you got it right. Your understanding for both cases is correct.

See the description of the Normalization name-value argument on either of the histogram or histcounts documentation pages. It describes exactly what the Values property of the histogram or the first output of the histcounts function represent.

Sim 2023-8-1

thanks @Steven Lord :-)

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