Histogram normalisation: a question about terminology
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num_bins = 30; % <-- note: I specify the "number of bins" and not the "bin width", which can be different from 1
% Case 1
histcounts(X,num_bins,'Normalization','probability');
histogram(X,'NumBins',num_bins,'Normalization','probability');
% Case 2
histcounts(X,num_bins,'Normalization','pdf');
histogram(X,'NumBins',num_bins,'Normalization','pdf');
Do I understand correctly that
- For Case 1, I get the "Relative Frequency Histogram" or an "empirical estimate of the Probability Mass Function"?
- For Case 2, - where I divide by the bin widths as well -, I get the an "empirical estimate of the Probability Density Function"?
回答（1 个）
Satwik Samayamantry
2023-7-14
0 个投票
Hi Sim,
Yeah you got it right. Your understanding for both cases is correct.
3 个评论
Steven Lord
2023-8-1
See the description of the Normalization name-value argument on either of the histogram or histcounts documentation pages. It describes exactly what the Values property of the histogram or the first output of the histcounts function represent.
Sim
2023-8-1
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