rounding elements in matrix if > or < to 0.75

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aldo
aldo 2023-7-17
评论： Dyuman Joshi 2023-7-18
example:
3.32==> .032 is < 0.75 ===> 3
0.78===>0.78 is >0.75==> 1

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回答（2 个）

Cris LaPierre
Cris LaPierre 2023-7-17
编辑：Cris LaPierre 2023-7-17
Ran in:
Currently, round uses 0.5 as the threshold. The quickest solution would be to modify your data by subtracting 0.25 to artificially move the threshold. Now, 0.75 become 0.5 and is still rounded up. 1.74 becomes 1.49, and is rounded down. In both cases, you end up with the value you want.
x = [3.32;0.78];
round(x-0.25)
ans = 2×1
3 1
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Cris LaPierre
Cris LaPierre 2023-7-17
You can determine if it works just by testing it. Do you get the expected results?
aldo
aldo 2023-7-17
ah ok...I'll have to do more appropriate numerical tests I'm bad at math :(

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Swapnil Tatiya
Swapnil Tatiya 2023-7-18
Ran in:
Hi @aldo,
you could use this as another way to round your numbers according to what you desire by doing the following
x=[0.33 0.45 1.56 1.77];
x=floor(x+0.25)
x = 1×4
0 0 1 2
Hope this helps!

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