Open a file error, even though path is valid and correct
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I am new to Matlab and had help writing my code, but even though the path is correct I cant get my file to open.
close all, clear all clc
% note I've renamed the files, call them what you like but they need to
% have the year in them to load in a loop
dir=('"C:\Users\Madison-Riley\Desktop\Copernicus Data"');
%look at one file to interrogate and understand dimensions and variables
ncdisp([dir,'June1972.nc'])
% test=ncread([filepath,'June2021.nc'],'uo'); whos test
% check all your files, June2019 only had one timestep so I couldn't work with that??
% same for June2020
time=ncread([filepath,'June2022.nc'],'time'); whos time
ntime=length(time);
% get coordinate data, assuming it's the same between all files
lon=ncread([filepath,'June2021.nc'],'longitude');
lat=ncread([filepath,'June2021.nc'],'latitude');
[LON,LAT]=meshgrid(lon,lat);
I don't understnad the issue. My file is coming from the exact directory and that is teh fil;e name. I am trying to create a mean across 50 years for June (1972-2022). June 1972 was sued to understand my dimensins and variables. June 2021 was used to recieve coordinate data.
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回答(1 个)
Walter Roberson
2023-7-18
Do not use the "" in the directory name.
dir = 'C:\Users\Madison-Riley\Desktop\Copernicus Data';
Do not put filenames together using [], use fullfile() instead
time = ncread(fullfile(filepath,'June2022.nc'),'time'); whos time
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Stephen23
2023-7-18
fp = 'C:\Users\Madison-Riley\Desktop\Copernicus Data';
ncdisp(fullfile(fp,'June1972.nc'))
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