error using tranpose (recieving permute error )
显示 更早的评论
CODE:
%% Testing Phase
load('testFeatures');
featvales=b2{1};
label=b2{2};
num_dims = max(size(featvales));
X=featvales';
Y=label';
PROBLEM:
I have to calculate the average for 2 different dimension
1st for 10 dimensional function
2nd for 30 dimensional function
ERROR :(the following error is recieved while executing the code)
Error using '
Transpose on ND array is not defined. Use PERMUTE instead.
Error in FeatureSelection (line 28)
X=featvales';
2 个评论
Walter Roberson
2023-7-26
num_dims = max(size(featvales));
That is incorrect.
num_dims = ndims(featvales);
Meetul Choudhary
2023-7-27
采纳的回答
The error message is clear. How do you transpose a three (or more) dimension array?
a=rand(2,3);
a';
a=rand(2,3,4);
a';
7 个评论
Meetul Choudhary
2023-7-26
Fangjun Jiang
2023-7-26
What is the return value of size(X)?
Your array "X" must be a multi-dimenstion array. In that case, you can't do transpose(X).
Meetul Choudhary
2023-7-27
Fangjun Jiang
2023-7-27
编辑：Fangjun Jiang
2023-7-27
add this line before doing the transpose. You will see it removes the two dimensions of length 1.
featvales=squeeze(featvales);
size(featvales)
Meetul Choudhary
2023-7-27
Fangjun Jiang
2023-7-27
Then you should be able to do featvales'
Meetul Choudhary
2023-7-28
编辑：Meetul Choudhary
2023-7-28
更多回答（1 个）
James Tursa
2023-7-26
编辑：James Tursa
2023-7-26
If you are trying to transpose the initial 2D pages of your variable, you can do this:
pagetranspose(featvales)
Or this:
d = 1:ndims(featvales)
permute(featvales,[2,1,d(3:end)])
But it isn't clear if this will fix your underlying problem.
2 个评论
Meetul Choudhary
2023-7-27
what exactly does this output gives as output?
it is showing a value for (:, :, 1, 704) to (:, :, 1000, 704)
Meetul Choudhary
2023-7-27
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