Extract numbers from a list
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Hi~
There is A=[1:1:37] in matlab, two numbers are randomly drawn from the list A simultaneously, and a total of 74 times are drawn. Requires are as fllows:
1. Each number is drawn 4 times in total.
2. And the same number will not appear twice every time you draw
3. The same number will not be drawn for two consecutive trials.
The final result is expressed as a 74×2 list, each row represents an extraction, the first column indicates the first number drawn, and the second column indicates the second number drawn.
6 个评论
Stephen23
2023-8-2
It looks like you will need a WHILE loop, or something similar. What have you tried so far?
Jane
2023-8-2
Stephen23
2023-8-2
"I wonder know how to fufill the reqirement 2?"
By specifying "Replace"=false you have already fulfilled requirement 2.
Jane
2023-8-2
"I misread it just now, it should be requirement three."
You could make a sample, then test if its elements are different compared to the last sample. If the values are duplicated make another sample (e.g. a WHILE loop).
However you should be thinking about requirement 1, because how you approach that will determine the entire structure of your algorithm and code, probably more than requirements 2 and 3.
Jane
2023-8-3
采纳的回答
succeed = false;
while ~succeed
c = repelem(4,37,1);
n = sum(c);
r = rand(1,n);
y = [];
for i=1:n
cn = c;
cn(y) = 0;
cc = cumsum(cn);
s = cc(end);
succeed = s > 0;
if ~succeed
break
end
x = discretize(r(i), [0; cc/s]);
r(i) = x;
c(x) = c(x)-1;
y = r(max(i-mod(i,2)-1,1):i);
end
end
r = reshape(r,2,[])';
r
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