Delete rows from a table below a certain threshold

60 次查看（过去 30 天）
Cathal
Cathal 2023-8-3
评论： Jon 2023-8-3
I have a double table with two columns, Time and Data. I want to delete values out of both columns in the table if it is below a certain value in the 'Data' column. The problem I am encountering is that the data column conatins large values and the time column contains small values so the code I'm using deletes the values from 'Data', working as intended, but then also wipes the entirety of the Time column as all the values are smaller than the threshold. How can I modfiy this to delete Time rows corresponding to the deleted Data rows and leave the rest?
Table = cat(2,Time,Data)
Threshold_Number = T
rowsToDelete = Table < T;
Table(rowsToDelete) = [];
  1 个评论
Dyuman Joshi
Dyuman Joshi 2023-8-3
编辑：Dyuman Joshi 2023-8-3
Numeric data variables are not called Tables in context of MATLAB.
If you have to compare the values in Data column to check, then why are you comparing the threshold with the whole array (3rd line of code above)?
Compare the first row, and use output as the row indices.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Voss
Voss 2023-8-3
Ran in:
% Example Time, Data and T:
Time = (1:10).';
Data = rand(10,1);
T = 0.5;
% Your code, modified:
Table = cat(2,Time,Data)
Table = 10×2
1.0000 0.0755 2.0000 0.8808 3.0000 0.9778 4.0000 0.0265 5.0000 0.8948 6.0000 0.1272 7.0000 0.8180 8.0000 0.8969 9.0000 0.8362 10.0000 0.7097
Threshold_Number = T;
rowsToDelete = Table(:,2) < T;
Table(rowsToDelete,:) = []
Table = 7×2
2.0000 0.8808 3.0000 0.9778 5.0000 0.8948 7.0000 0.8180 8.0000 0.8969 9.0000 0.8362 10.0000 0.7097
  3 个评论
显示 1更早的评论
Voss
Voss 2023-8-3
Not that I know of.
I added my answer mostly to show the OP that their approach (deleting the rows) would work fine once the indexing was done correctly.
In my opinion, in general it's best to change as little as necessary from the OP's original approach - change only whatever is necessary to get the code to work. A beginner may not know what changes were relevant to the problem at hand and which were more just stylistic choices.
Jon
Jon 2023-8-3
Good point. I hadn't noticed that the original post also used the assignment to empty matrix. In the future, I'll try to pay more attention to staying as close to OP's posts as possible, and then if there is a better way, suggest that as an alternative. -Thanks!

请先登录，再进行评论。

更多回答（1 个）

Jon
Jon 2023-8-3
编辑：Jon 2023-8-3
Ran in:
% Make up some example data
Time = [1:10]';
Data = randn(10,1)*10;
Table = cat(2,Time,Data)
Table = 10×2
1.0000 -6.2349 2.0000 -17.9289 3.0000 6.4076 4.0000 -3.3890 5.0000 3.9484 6.0000 1.0207 7.0000 17.3471 8.0000 14.6419 9.0000 0.5553 10.0000 15.1793
Threshold = 8;
% Delete rows where Data is less than threshold
% (actually we are keeping only rows where Data is bigger than threshold)
Table = Table(abs(Data)>Threshold,:)
Table = 4×2
2.0000 -17.9289 7.0000 17.3471 8.0000 14.6419 10.0000 15.1793
Here I have followed your code, but I would suggest not calling your variable "Table", when in fact it is an array.

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

产品


版本

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by