how to create group from matrix
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hi, i want to do table group :
1 column :3,5,9,12
2 column: 4,6,7,8,10,11
3 colum (no..because this element are identical at colum 1 )
..
the column with all zero element to be not insert! (and the column egual )
finally i get this matrix (colum 5,6,7,8 are clone...i not insert it in the group)
1 column :3,5,9,12,0,0
2 column: 4,6,7,8,10,11
i try to use world reserved "unique" but i can't do it
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M = [0 0 3 4 3 4 4 4; 0 0 5 6 5 6 6 6; 0 0 9 7 9 7 7 7; 0 0 12 8 12 8 8 8; 0 0 0 10 0 10 10 10; 0 0 0 11 0 11 11 11; 0 0 0 0 0 0 0 0; 0 0 0 0 0 0 0 0; 0 0 0 0 0 0 0 0]
% unique() by column:
M = unique(M.','rows','stable').'
% remove all-0 rows:
M(all(M == 0,2),:) = [];
% remove all-0 columns:
M(:,all(M == 0,1)) = [];
disp(M);
4 个评论
Voss
2023-8-7
.' is transpose
' is complex conjugate transpose
By removing the . you went from using tranpose to complex conjugate transpose, which means that the code will not work as intended for complex-valued matrices. But since your matrix is real-valued its complex conjugate is itself so the result is the same whether you use .' or ' in this case.
pipin
2023-8-7
Voss
2023-8-7
You're welcome!
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