How can I select two out of 6 points for every page without loops?
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I am trying to select two out of 6 points in an array whose size is 6x3xn. These two points are not in the same row on each page as I am trying to select those two of the six points that meet a certain condition. Let's assume that condition is that every coordinate is between 0 and 30.
Is there away to do this without loops?
8 个评论
Bruno Luong
2023-8-11
编辑:Bruno Luong
2023-8-11
So the number of pages that satisfies that (exactly 2 rows are find) would reduce. And you might keep track of which of those are not discarded, which are.
Your discription "... for every page" "...on each page" are missleading if not wrong.
采纳的回答
Jan
2023-8-10
n = 2;
X = randi(40, 6, 3, n)
mask = all(X >= 0 & X <= 30, 2)
Y = reshape(X(cat(2, mask, mask, mask)), [], 3)
6 个评论
Bruno Luong
2023-8-15
编辑:Bruno Luong
2023-8-15
OK this looks correct. But I don't think you need permute and transpose at all. It seems like a side effect of your though trying to fix Jan's coden but that is not relevant.
n = 4;
nsolperpage = 2;
X = randi(40, [6, 3, n])
mask = all(X >= 0 & X <= 30, 2);
keep = sum(mask,1) == nsolperpage;
extractpages = find(keep)
mask(:,:,~keep) = false;
Y = reshape(X([mask, mask, mask]), nsolperpage, 3, [])
更多回答(1 个)
Bruno Luong
2023-8-15
n = 4;
nsolperpage = 2;
X = randi(40, [6, 3, n])
mask = all(X >= 0 & X <= 30, 2);
[~,p] = find(reshape(mask, [], n));
count = accumarray(p, 1, [n 1]);
keep = count == nsolperpage;
extractpages = find(keep)
mask(:,:,~keep) = false;
Y = reshape(X([mask, mask, mask]), nsolperpage, 3, [])
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