How can I extract multiple rows from an array at regular intervals?

2023 8 11
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更新时间：2023 8 11
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If I have a simple 72x10 array, how can I make a new array that is made up of the first 6 rows, then miss the next 6, then take the next 6 etc. to the end.
If the main array was A, I know B = A(1:6:end,:)would extract me every 6th row for example, but I want to take a 6-row selection of rows. Output B should be 36x10 (i.e. halved in row length)

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Adam Danz
Adam Danz 2023-8-11
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Create demo matrix A
A = (1:72)'.*ones(1,10)
A = 72×10
1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 4 4 4 4 4 4 4 4 4 4 5 5 5 5 5 5 5 5 5 5 6 6 6 6 6 6 6 6 6 6 7 7 7 7 7 7 7 7 7 7 8 8 8 8 8 8 8 8 8 8 9 9 9 9 9 9 9 9 9 9 10 10 10 10 10 10 10 10 10 10
size(A)
ans = 1×2
72 10
Extract rows 1:6, 13:18, ...
q = 6;
idxMat = reshape(1:q*floor(height(A)/q),q,[]);
idx = idxMat(:,[1:2:end]);
B = A(idx,:)
B = 36×10
1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 4 4 4 4 4 4 4 4 4 4 5 5 5 5 5 5 5 5 5 5 6 6 6 6 6 6 6 6 6 6 13 13 13 13 13 13 13 13 13 13 14 14 14 14 14 14 14 14 14 14 15 15 15 15 15 15 15 15 15 15 16 16 16 16 16 16 16 16 16 16
size(B)
ans = 1×2
36 10

更多回答（1 个）

Bruno Luong
Bruno Luong 2023-8-11
移动：Adam Danz 2023-8-11
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Ran in:
No need for reshape and repmat, etc...
A = reshape(1:720, 72, 10);
B = A((0:12:66) + (1:6)', :) % 66 is size(A,1)-6
B = 36×10
1 73 145 217 289 361 433 505 577 649 2 74 146 218 290 362 434 506 578 650 3 75 147 219 291 363 435 507 579 651 4 76 148 220 292 364 436 508 580 652 5 77 149 221 293 365 437 509 581 653 6 78 150 222 294 366 438 510 582 654 13 85 157 229 301 373 445 517 589 661 14 86 158 230 302 374 446 518 590 662 15 87 159 231 303 375 447 519 591 663 16 88 160 232 304 376 448 520 592 664

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