Related vector values via cell array

Question

Sergio Rojas Blanco 2023-8-12

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2007752-related-vector-values-via-cell-array

评论： Dyuman Joshi 2023-8-12

采纳的回答： Dyuman Joshi

在 MATLAB Online 中打开

Hi guys, I hope someone can help me:

I have a vector. Suppose this:

A=(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)'

Some values of this vector are related through a cell array, in such a way that a value of the vector is the index of a cell. I need to know if a value of the vector "a" is related to another value "b".

B={15, 12, 0, [11, 7], 9, 0, [1, 20, 21], 18, 7, 0, 16, [13, 14], 17, 4, 6};
a=2; b=7

In this case, 2 and 7 are related:

Index       Value
           12
          13,14
          17
          Nan
          4
           7

So, a=5 and b=6; and a=4 and b=1 are also related.

Thanks to the whole community

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Sergio Rojas Blanco 2023-8-12

You're rigth. I have edited to remove the error

Dyuman Joshi 2023-8-12

编辑：Dyuman Joshi 2023-8-12

@Sergio Rojas Blanco, please check my answer.

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Answer 1

Dyuman Joshi 2023-8-12

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2007752-related-vector-values-via-cell-array#answer_1286782

在 MATLAB Online 中打开

A=(1:10)';
B={15, 12, 0, [11, 7], 9, 0, [1, 20, 21], 18, 7, 0, 16, [13, 14], 17, 4, 6};
m = max([B{:}]);
z1 = nested(A,B,2,7)
z1 = 1
%8th index is 18 which is greater than the number of elements
%so no value is related to it
z2 = nested(A,B,8,randi(m))
z2 = 0
%3rd index is 0, so no value related to it
z3 = nested(A,B,3,randi(m))
z3 = 0
%Similarly for 6th index
z4 = nested(A,B,6,randi(m))
z4 = 0
z5 = nested(A,B,5,6)
z5 = 1
%As the 1st index in B goes to the 6th index, no value will be related to it as well
z6 = nested(A,B,1,randi(m))
z6 = 0
function z = nested(A,B,a,b)
%Returns 0 if not related, 1 if related
%Initialize z as 0
z=0;
nB=numel(B);
for m=1:numel(a)
    %Assign only if the value is within the range of number of elements of B
    if a(m)<=nB && a(m)>0
        c=B{a(m)};
    else
    %If the value is not in the range, skip to the next iteration
        continue
    end
    %Check if b is present in c or not
    if ismember(b,c)
        z=1;
        return
    else
    %If not present, continue the recursion and keep checking
        z=nested(A,B,c,b);
        end
    end
end