why does the function in my programming get an error with the description 'Not enough input arguments.'?
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why does the function in my programming get an error with the description 'Not enough input arguments.' please explain why this can be an error and how to fix it? I am using matlab R2015a.
function letter = readLetter(snap)
load NewTemplates
snap=imresize(snap,[42 24]);
comp=[ ];
for n=1:length(NewTemplates)
sem=corr2(NewTemplates{1,n},snap);
comp=[comp sem];
end
vd=find(comp==max(comp));
if vd==1 || vd==2
letter='A';
elseif vd==3 || vd==4
letter='B';
elseif vd==5
letter='C';
elseif vd==6 || vd==7
letter='D';
elseif vd==8
letter='E';
elseif vd==9
letter='F';
elseif vd==10
letter='G';
elseif vd==11
letter='H';
elseif vd==12
letter='I';
elseif vd==13
letter='J';
elseif vd==14
letter='K';
elseif vd==15
letter='L';
elseif vd==16
letter='M';
elseif vd==17
letter='N';
elseif vd==18 || vd==19
letter='O';
elseif vd==20 || vd==21
letter='P';
elseif vd==22 || vd==23
letter='Q';
elseif vd==24 || vd==25
letter='R';
elseif vd==26
letter='S';
elseif vd==27
letter='T';
elseif vd==28
letter='U';
elseif vd==29
letter='V';
elseif vd==30
letter='W';
elseif vd==31
letter='X';
elseif vd==32
letter='Y';
elseif vd==33
letter='Z';
elseif vd==34
letter='1';
elseif vd==35
letter='2';
elseif vd==36
letter='3';
elseif vd==37 || vd==38
letter='4';
elseif vd==39
letter='5';
elseif vd==40 || vd==41 || vd==42
letter='6';
elseif vd==43
letter='7';
elseif vd==44 || vd==45
letter='8';
elseif vd==46 || vd==47 || vd==48
letter='9';
else
letter='0';
end
end
4 个评论
Torsten
2023-8-14
Did you call the function from a script with an appropriate input for "snap" ? Otherwise: how should the function work without input ?
Amelinda Callista
2023-8-20
Walter Roberson
2023-8-21
Why does everyone use that verbose code??
function letter = readLetter(snap)
load NewTemplates
snap=imresize(snap,[42 24]);
comp=[ ];
for n=1:length(NewTemplates)
sem=corr2(NewTemplates{1,n},snap);
comp=[comp sem];
end
vd=find(comp==max(comp));
LETS = 'AABBCDDEFGHIJKLMNOOPPQQRRSTUVWXYZ123445666788999';
if vd <= length(LETS)
letter = LETS(vd);
else
letter = '0';
end
Amelinda Callista
2023-8-22
回答（1 个）
Sulaymon Eshkabilov
2023-8-14
What Torsten has suggested is somewhat like this one. And addionally, it is better to have two input arguments (to be called, or existing in the workspace), e.g.:
NewTemplates = load('XXXXX.mat'); % mat or ASCII formatted *.dat files can be loaded
letter = readLetter(snap, NewTemplates);
function letter = readLetter(snap, NewTemplates)
snap=imresize(snap,[42 24]);
...
end
7 个评论
Amelinda Callista
2023-8-20
I guess you mean "row" instead of "column" ?
Which MATLAB version do you use ?
Walter Roberson
2023-8-20
you are using r2015a. But r2015b was the first release that permitted defining functions inside scripts. You need to put the function in its own file in your release.
Torsten
2023-8-20
I wonder why the above link is not yet updated (at least said that it's only relevant for releases <= 2015a).
Amelinda Callista
2023-8-21
"what version of matlab should I use so that the function doesn't have problems?"
MATLAB has supported functions for a very long time (certainly well before your version), so there is nothing stopping you from creating a function in its own file and then calling it, exactly as Walter Roberson commented here.
Amelinda Callista
2023-8-21
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