Remove zeros from a vector from a specific position
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Hello, I have the following vector as example:
X=[0, 0; 0.02, 2.3;0.04, 0.4; 0, 0; 0.06, 2.5; 0.08, 3.6; 0, 0; 0.10, 2.5]
I want to remove the zeros and I only want to keep the zeros at the beginning and obtain the following matrix:
X=[0, 0; 0.02, 2.3;0.04, 0.4; 0.06, 2.5; 0.08, 3.6; 0.10, 2.5]
I know this option
X( all(~X,2), : ) = [];
which eliminates all the zeros and then I can add the zeros again at the beggining using
X=vertcat([0 0],X);
but there must be a direct way to do it. I would appreciate the help.
2 个评论
the cyclist
2023-8-18
Will there always be at least one row of zeros at the beginning?
If so, will there always be exactly one row of zeros at the beginning?
Jorge Luis Paredes Estacio
2023-8-18
采纳的回答
Bruno Luong
2023-8-18
remove = all(~X,2);
remove(1) = false;
X(remove,:) = [];
6 个评论
Jorge Luis Paredes Estacio
2023-8-18
Bruno Luong
2023-8-18
编辑：Bruno Luong
2023-8-18
One liner
X([false;all(~X(2:end,:),2)],:)=[];
Jorge Luis Paredes Estacio
2023-8-18
Bruno Luong
2023-8-18
Fixed
Jorge Luis Paredes Estacio
2023-8-18
FYI, this solution will not work if there are multiple rows of leading zeros to keep. (That's why I asked if there was always exactly one row of leading zeros.) For example,
X = [0, 0;
0, 0;
2, 3;
5, 7;
0, 0];
X([false;all(~X(2:end,:),2)],:)=[]
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