NONLCON must be a function using lsqnonlin
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Hello everyone!
I am trying to estimate parameters using lsqnonlin and I get the following error:
Error using cnls
NONLCON must be a function
Error in lsqnonlin (line 220)
[xCurrent,Resnorm,FVAL,EXITFLAG,OUTPUT,LAMBDA,JACOB] = cnls(caller, FUN,xCurrent,A,B,Aeq,Beq,LB,UB,NONLCON, ...
I have no nonlinear constraints and therefore I left NONLCON as empty square brackets. I don't understand where I am going wrong.
The error occurs on line 70.
采纳的回答
No, you have set the nonlcon argument to Cexp which is a numeric vector. You should review the documentation for the correct ordering if the arguments.
6 个评论
Possibly this is what you meant to have:
fun=@(x)resfun(x,texp,Initial,Data,Spatial,Cexp);
[OptimalParameters, SSEout] = lsqnonlin(fun,InitGuess,lb,ub);
James99
2023-8-28
Matt J
2023-8-28
How fast are your objective function evaluations?
James99
2023-8-28
Matt J
2023-8-28
If the optimization time is long, it doesn't necessarily mean you have slow convergence. If one execution of resfun takes a long time, that will also make the optimization time longer.
James99
2023-8-28
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