pie chart creation with name (number) and corresponding percentage

Question

Alberto Acri 2023-8-30

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2014991-pie-chart-creation-with-name-number-and-corresponding-percentage

回答： Benjamin Kraus 2024-4-26

采纳的回答： Star Strider

在 MATLAB Online 中打开

Hi! I would like to create a pie chart like in the present demo:

x = [1,2,3];

p = pie(x);

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

txt = {'Item A: ';'Item B: ';'Item C: '};

combinedtxt = strcat(txt,percentValues);

pText(1).String = combinedtxt(1);

pText(2).String = combinedtxt(2);

pText(3).String = combinedtxt(3);

How can I achieve the same result with my data?

I tried it this way:

number = [78;79;80;81;82;83;84;85;86;87;88]';

value = [4509;5239;6400;9074;11047;13147;15137;13909;6354;1152;183]';

number2 = {};

for K = 1:height(number)

number1 = sprintf('%.0f',number(K));

number2 = [number2,{number1}];

end

number2 = number2.';

p = pie(value);

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

combinedtxt = strcat(number2,percentValues);

for K = 1:height(value)

pText(K).String = combinedtxt(K);

end

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Answer 1

Star Strider 2023-8-30

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2014991-pie-chart-creation-with-name-number-and-corresponding-percentage#answer_1297516

编辑：Star Strider 2023-8-30

在 MATLAB Online 中打开

One approach —

number = [78;79;80;81;82;83;84;85;86;87;88]';

value = [4509;5239;6400;9074;11047;13147;15137;13909;6354;1152;183]';

f = figure;

p = pie(value);

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

delete(f)

pcts = regexp(percentValues, '\d*', 'match');

pcts = cellfun(@(x)str2double(x), pcts);

idx = pcts<7;

combine = number(idx);

pctv = pcts(idx);

percentVals = compose(' (%d%%)',pcts(~idx));

percentVals{end+1} = [' (' num2str(sum(pctv)) '%)'];

nrc = compose('%d ', number(~idx)).';

nrc{end+1} = [num2str(combine) ' '];

cattxt = cellfun(@(x,y)cat(2,x,y),nrc, percentVals, 'Unif',0);

pText(numel(cattxt)+1:end) = [];

value2 = [value(~idx) sum(value(idx))];

figure

p = pie(value2);

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

for k = 1:numel(cattxt)

pText(k).String = cattxt(k);

end

.

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Star Strider 2023-8-31

在 MATLAB Online 中打开

As always, my pleasure!

That simply requires a few modifications of my current code (and a reference to the pie documentation section on Compare Two Pie Charts to add the legend).

Try this —

number = [78;79;80;81;82;83;84;85;86;87;88]';

value = [4509;5239;6400;9074;11047;13147;15137;13909;6354;1152;183]';

f = figure;

p = pie(value);

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

delete(f)

pcts = regexp(percentValues, '\d*', 'match');

pcts = cellfun(@(x)str2double(x), pcts);

idx = pcts<7;

combine = number(idx);

pctv = pcts(idx);

percentVals = compose(' (%d%%)',pcts(~idx));

percentVals{end+1} = [' (' num2str(sum(pctv)) '%)'];

nrc = compose('%d ', number(~idx)).';

nrc{end+1} = [num2str(combine) ' '];

cattxt = cellfun(@(x,y)cat(2,x,y),nrc, percentVals, 'Unif',0); % Originally Segment Labels, Now 'legend' Text

pText(numel(cattxt)+1:end) = [];

value2 = [value(~idx) sum(value(idx))];

figure

p = pie(value2);

pPatch = findobj(p, 'Type','Patch');

cm = colormap(turbo(numel(pPatch))); % Colour Array (Can Be Whatever You Define It To Be)

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

for k = 1:numel(cattxt)

pPatch(k).FaceColor = cm(k,:); % Colour Each Patch Individually

pText(k).String = []; % Delete The 'String' Labels

end

legend(cattxt, 'Location','eastoutside')

.

Star Strider 2023-9-1

在 MATLAB Online 中打开

Thank you!

That requires replacing this assignment:

nrc{end+1} = [num2str(combine) ' ']

with this one:

nrc{end+1} = sprintf('%d %d\n%d %d ',combine); % NEW 'nrc{end+1}'

or this one:

nrc{end+1} = sprintf('%d %d (%2d%%)\n%d %d',[combine(1:2) sum(pcts(idx)) combine(3:4)]) % NEW 'nrc{end+1}'

To get different versions, change the format specifier string.

I changed the others as well, since with a new compose call and with sprintf for the last element in ‘nrc’, ‘cattxt’ is no longer necessary. To avoid re-writing the rest of the code, I just set:

cattxt = nrc;

Try this —

number = [78;79;80;81;82;83;84;85;86;87;88]';

value = [4509;5239;6400;9074;11047;13147;15137;13909;6354;1152;183]';

f = figure;

p = pie(value);

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

delete(f)

pcts = regexp(percentValues, '\d*', 'match');

pcts = cellfun(@(x)str2double(x), pcts);

idx = pcts<7;

combine = number(idx);

pctv = pcts(idx);

percentVals = compose(' (%d%%)',pcts(~idx));

percentVals{end+1} = [' (' num2str(sum(pctv)) '%)'];

nrc = compose('%d (%2d%%)', [number(~idx).', pcts(~idx)]);

% return

% nrc{end+1} = [num2str(combine) ' ']

nrc{end+1} = sprintf('%d %d (%2d%%)\n%d %d',[combine(1:2) sum(pcts(idx)) combine(3:4)]); % NEW 'nrc{end+1}'

% cattxt = cellfun(@(x,y)cat(2,x,y),nrc, percentVals, 'Unif',0); % Originally Segment Labels, Now 'legend' Text

cattxt = nrc;

pText(numel(cattxt)+1:end) = [];

value2 = [value(~idx) sum(value(idx))];

figure

p = pie(value2);

pPatch = findobj(p, 'Type','Patch');

cm = colormap(turbo(numel(pPatch))); % Colour Array (Can Be Whatever You Define It To Be)

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

for k = 1:numel(cattxt)

pPatch(k).FaceColor = cm(k,:); % Colour Each Patch Individually

pText(k).String = []; % Delete The 'String' Labels

end

legend(cattxt, 'Location','eastoutside')

.

Star Strider 2023-9-2

在 MATLAB Online 中打开

As always, my pleasure!

The last legend entry is controlled by this line:

nrc{end+1} = sprintf('%d %d (%2d%%)\n%d %d',[combine(1:2) sum(pcts(idx)) combine(3:4)]); % NEW 'nrc{end+1}'

so you can change the format descriptor string to an extent, for example:

nrc{end+1} = sprintf('%d %d %d (%2d%%)\n%d %d',[combine(1:3) sum(pcts(idx)) combine(4)]); % NEW 'nrc{end+1}'

however the placement with respect to the associated coloured patch bar is likely not an option. It has to be like one of the first two images. (My source for such information is Undocumented MATLAB and it has no information on this.) Adding an ‘invisible’ patch like that to the legend may not be possible without also adding it to the pie chart. The legend function has an undocumented second output that allows for some slight changes, however not what you want to do (I did that experiment, and it failed).

It is possible to get them to line up like you want by changing the edit descriptor string in ‘nrc{end+1}’, (adding a leading '\n') however that leaves a gap above the last patch —

number = [78;79;80;81;82;83;84;85;86;87;88]';

value = [4509;5239;6400;9074;11047;13147;15137;13909;6354;1152;183]';

f = figure;

p = pie(value);

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

delete(f)

pcts = regexp(percentValues, '\d*', 'match');

pcts = cellfun(@(x)str2double(x), pcts);

idx = pcts<7;

combine = number(idx);

pctv = pcts(idx);

percentVals = compose(' (%d%%)',pcts(~idx));

percentVals{end+1} = [' (' num2str(sum(pctv)) '%)'];

nrc = compose('%d (%2d%%)', [number(~idx).', pcts(~idx)]);

% return

% nrc{end+1} = [num2str(combine) ' ']

nrc{end+1} = sprintf('\n%d %d (%2d%%)\n%d %d',[combine(1:2) sum(pcts(idx)) combine(3:4)]); % NEW 'nrc{end+1}'

% cattxt = cellfun(@(x,y)cat(2,x,y),nrc, percentVals, 'Unif',0); % Originally Segment Labels, Now 'legend' Text

cattxt = nrc;

pText(numel(cattxt)+1:end) = [];

value2 = [value(~idx) sum(value(idx))];

figure

p = pie(value2);

pPatch = findobj(p, 'Type','Patch');

cm = colormap(turbo(numel(pPatch))); % Colour Array (Can Be Whatever You Define It To Be)

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

for k = 1:numel(cattxt)

pPatch(k).FaceColor = cm(k,:); % Colour Each Patch Individually

pText(k).String = []; % Delete The 'String' Labels

end

legend(cattxt, 'Location','eastoutside')

.

Star Strider 2023-9-2

在 MATLAB Online 中打开

As always, my pleasure!

You just need to change the format descriptor in the sprintf call in ‘nrc{end+1}’ in various ways —

number = [78;79;80;81;82;83;84;85;86;87;88]';

value = [4509;5239;6400;9074;11047;13147;15137;13909;6354;1152;183]';

f = figure;

p = pie(value);

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

delete(f)

pcts = regexp(percentValues, '\d*', 'match');

pcts = cellfun(@(x)str2double(x), pcts);

idx = pcts<7;

combine = number(idx);

pctv = pcts(idx);

percentVals = compose(' (%d%%)',pcts(~idx));

percentVals{end+1} = [' (' num2str(sum(pctv)) '%)'];

nrc = compose('%d (%2d%%)', [number(~idx).', pcts(~idx)]);

% return

% nrc{end+1} = [num2str(combine) ' ']

nrc{end+1} = sprintf('\n%d %d %d (%2d%%)\n%d',[combine(1:2) sum(pcts(idx)) combine(3:4)]); % NEW 'nrc{end+1}'

% cattxt = cellfun(@(x,y)cat(2,x,y),nrc, percentVals, 'Unif',0); % Originally Segment Labels, Now 'legend' Text

cattxt = nrc;

pText(numel(cattxt)+1:end) = [];

value2 = [value(~idx) sum(value(idx))];

figure

p = pie(value2);

pPatch = findobj(p, 'Type','Patch');

cm = colormap(turbo(numel(pPatch))); % Colour Array (Can Be Whatever You Define It To Be)

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

for k = 1:numel(cattxt)

pPatch(k).FaceColor = cm(k,:); % Colour Each Patch Individually

pText(k).String = []; % Delete The 'String' Labels

end

legend(cattxt, 'Location','eastoutside')

% Previous 'nrc{end+1}' is now 'nrc{end}' In This Illustration —

nrc{end} = sprintf('\n\n\n%d (%2d%%)\n%d\n%d\n%d',[combine(1) sum(pcts(idx)) combine(2:4)]); % NEW 'nrc{end+1}'

cattxt = nrc;

figure

p = pie(value2);

pPatch = findobj(p, 'Type','Patch');

cm = colormap(turbo(numel(pPatch))); % Colour Array (Can Be Whatever You Define It To Be)

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

for k = 1:numel(cattxt)

pPatch(k).FaceColor = cm(k,:); % Colour Each Patch Individually

pText(k).String = []; % Delete The 'String' Labels

end

legend(cattxt, 'Location','eastoutside')

% Previous 'nrc{end+1}' is now 'nrc{end}' In This Illustration —

nrc{end} = sprintf('%d %d %d %d (%2d%%)',[combine sum(pcts(idx))]); % NEW 'nrc{end+1}'

cattxt = nrc;

figure

p = pie(value2);

pPatch = findobj(p, 'Type','Patch');

cm = colormap(turbo(numel(pPatch))); % Colour Array (Can Be Whatever You Define It To Be)

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

for k = 1:numel(cattxt)

pPatch(k).FaceColor = cm(k,:); % Colour Each Patch Individually

pText(k).String = []; % Delete The 'String' Labels

end

legend(cattxt, 'Location','eastoutside')

That is as close as I can get the last element to what you want. I cannot do anything about the extra spaces.

.

Alberto Acri 2023-9-3

编辑：Alberto Acri 2023-9-3

在 MATLAB Online 中打开

OK, the result is good enough for me!

One last info: with a different dataset I have a problem regarding the display of <7% values in the legend.

I tried using the line of code you showed me earlier but I get a layout that is not correct. I'll leave you the code I used:

number = [48	49	50	51	52	53	54	55	56	57	58	59	60	61	62	63	64	65	66	67	68	69	70	71	72	73	74	75	76	77	78	79	80	81	82	83	84	85	86	87	88];
value = [0	0	0	0	0	0	42	91	152	276	440	572	821	1155	1580	1761	2157	2256	2578	2499	2715	2794	3280	3237	3263	3586	3334	3652	3675	4404	4509	5239	6400	9074	11047	13147	15137	13909	6354	1152	183];
f = figure;
p = pie(value);
pText = findobj(p,'Type','text');
percentValues = get(pText,'String'); 
delete(f)
pcts = regexp(percentValues, '\d*', 'match');
pcts = cellfun(@(x)str2double(x), pcts);
idx = pcts<7;
combine = number(idx);
pctv = pcts(idx);
percentVals = compose(' (%d%%)',pcts(~idx));
percentVals{end+1} = [' (' num2str(sum(pctv)) '%)'];
nrc = compose('%d (%2d%%)', [number(~idx).', pcts(~idx)]);
% VARIED
nrc{end+1} = sprintf('%d %d %d %d %d (%2d%%)\n%d %d %d %d %d',[combine(1:5) sum(pcts(idx)) combine(6:end)]);    % NEW 'nrc{end+1}'
cattxt = nrc;
pText(numel(cattxt)+1:end) = [];
value2 = [value(~idx) sum(value(idx))];
figure
p = pie(value2);
pPatch = findobj(p, 'Type','Patch');
cm = colormap(turbo(numel(pPatch)));                                % Colour Array (Can Be Whatever You Define It To Be)
pText = findobj(p,'Type','text');
percentValues = get(pText,'String');
for k = 1:numel(cattxt)
    pPatch(k).FaceColor  = cm(k,:);                                 % Colour Each Patch Individually
    pText(k).String = [];                                           % Delete The 'String' Labels
end
lgd = legend(cattxt, 'Location','eastoutside','FontSize',12);

I really wanted to get this:

Is this something workable?

Also, I noted that the total comes 107% (7+8+10+11+10+61).

Star Strider 2023-9-3

在 MATLAB Online 中打开

Thank you!

You need to change ‘nrc{end+1}’ to accommodate the new ‘combine’ vector:

nrc{end+1} = sprintf('%d %d %d %d %d %d (%2d%%)\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d',[combine(1:6) sum(pcts(idx)) combine(7:end)]); % NEW 'nrc{end+1}'

Here, I used a (6x6) array for the numbers, since ‘combine’ is now a (1x36) vector. Change it to do whatever works best for you.

Try this —

number = [48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88];

value = [0 0 0 0 0 0 42 91 152 276 440 572 821 1155 1580 1761 2157 2256 2578 2499 2715 2794 3280 3237 3263 3586 3334 3652 3675 4404 4509 5239 6400 9074 11047 13147 15137 13909 6354 1152 183];

f = figure;

p = pie(value);

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

delete(f)

pcts = regexp(percentValues, '\d*', 'match');

pcts = cellfun(@(x)str2double(x), pcts);

idx = pcts<7;

combine = number(idx);

pctv = pcts(idx);

percentVals = compose(' (%d%%)',pcts(~idx));

percentVals{end+1} = [' (' num2str(sum(pctv)) '%)'];

nrc = compose('%d (%2d%%)', [number(~idx).', pcts(~idx)]);

% VARIED

nrc{end+1} = sprintf('%d %d %d %d %d %d (%2d%%)\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d',[combine(1:6) sum(pcts(idx)) combine(7:end)]); % NEW 'nrc{end+1}'

cattxt = nrc;

pText(numel(cattxt)+1:end) = [];

value2 = [value(~idx) sum(value(idx))];

figure

p = pie(value2);

pPatch = findobj(p, 'Type','Patch');

cm = colormap(turbo(numel(pPatch))); % Colour Array (Can Be Whatever You Define It To Be)

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

for k = 1:numel(cattxt)

pPatch(k).FaceColor = cm(k,:); % Colour Each Patch Individually

pText(k).String = []; % Delete The 'String' Labels

end

lgd = legend(cattxt, 'Location','eastoutside','FontSize',12);

.

Star Strider 2023-9-4

在 MATLAB Online 中打开

That may not be possible. I tried my own version, and I don’t get exactly the same results the pie gets, although my calculations otherwise work —

number = [48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88];

value = [0 0 0 0 0 0 42 91 152 276 440 572 821 1155 1580 1761 2157 2256 2578 2499 2715 2794 3280 3237 3263 3586 3334 3652 3675 4404 4509 5239 6400 9074 11047 13147 15137 13909 6354 1152 183];

f = figure;

p = pie(value);

[U_value,nidx,ix] = unique(value,'stable');

Counts = accumarray(ix, value);

sum_Counts = sum(Counts);

Freqs = Counts/sum(Counts) * 100;

[v1,v2] = bounds(Freqs)

v1 = 0

v2 = 11.0917

number_v = number(nidx).';

Interim_Results = table(number_v,Counts,Freqs)

Interim_Results = 36×3 table

number_v Counts Freqs ________ ______ ________ 48 0 0 54 42 0.030776 55 91 0.066681 56 152 0.11138 57 276 0.20224 58 440 0.32241 59 572 0.41914 60 821 0.60159 61 1155 0.84633 62 1580 1.1578 63 1761 1.2904 64 2157 1.5806 65 2256 1.6531 66 2578 1.889 67 2499 1.8312 68 2715 1.9894

Freqs_lt_7 = Freqs < 7; % Threshold Results

Thresholded_Interim_Results_1 = sum(Freqs(Freqs_lt_7))

Thresholded_Interim_Results_1 = 60.9880

Thresholded_Interim_Results_2 = [number_v(~Freqs_lt_7) Freqs(~Freqs_lt_7) round(Freqs(~Freqs_lt_7))];

Thresholded_Interim_Results_2(end+1,:) = [NaN sum(Thresholded_Interim_Results_2(:,2:end))]

Thresholded_Interim_Results_2 = 5×3

82.0000 8.0948 8.0000 83.0000 9.6335 10.0000 84.0000 11.0917 11.0000 85.0000 10.1919 10.0000 NaN 39.0120 39.0000

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

delete(f)

pcts = regexp(percentValues, '\d*', 'match');

pcts = cellfun(@(x)str2double(x), pcts);

idx = pcts<7;

combine = number(idx);

pctv = pcts(idx);

percentVals = compose(' (%d%%)',pcts(~idx));

percentVals{end+1} = [' (' num2str(sum(pctv)) '%)'];

nrc = compose('%d (%2d%%)', [number(~idx).', pcts(~idx)]);

% VARIED

nrc{end+1} = sprintf('%d %d %d %d %d %d (%2d%%)\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d',[combine(1:6) sum(pcts(idx)) combine(7:end)]); % NEW 'nrc{end+1}'

cattxt = nrc;

pText(numel(cattxt)+1:end) = [];

value2 = [value(~idx) sum(value(idx))];

figure

p = pie(value2);

pPatch = findobj(p, 'Type','Patch');

cm = colormap(turbo(numel(pPatch))); % Colour Array (Can Be Whatever You Define It To Be)

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

for k = 1:numel(cattxt)

pPatch(k).FaceColor = cm(k,:); % Colour Each Patch Individually

pText(k).String = []; % Delete The 'String' Labels

end

lgd = legend(cattxt, 'Location','eastoutside','FontSize',12);

.

Voss 2023-9-4

编辑：Voss 2023-9-4

在 MATLAB Online 中打开

@Alberto Acri: The numbers sum to 107 because the first (deleted) pie chart includes several strings that are "<1%". When you get the number from those strings and use it, of course those are counted as 1 instead of what they really are. The solution is, instead of getting the percentages from a pie chart you're going to delete, just calculate the percentages directly, and they'll have a higher precision. You'll have to round them when you use them in the legend, but here's the important part: the small ones (<1%) do not get "rounded" to 1 and then summed; instead you sum them first and then round the result. You can see below that the total sum is 100:

number = [48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88];

value = [0 0 0 0 0 0 42 91 152 276 440 572 821 1155 1580 1761 2157 2256 2578 2499 2715 2794 3280 3237 3263 3586 3334 3652 3675 4404 4509 5239 6400 9074 11047 13147 15137 13909 6354 1152 183];

% calculate percentages:

pcts = 100*value.'/sum(value);

idx = round(pcts)<7;

combine = number(idx);

pctv = pcts(idx);

nrc = compose('%d (%2d%%)', [number(~idx).', round(pcts(~idx))]);

% VARIED

nrc{end+1} = sprintf('%d %d %d %d %d %d (%2d%%)\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d\n%d %d %d %d %d %d',[combine(1:6) round(sum(pcts(idx))) combine(7:end)]); % NEW 'nrc{end+1}'

cattxt = nrc;

value2 = [value(~idx) sum(value(idx))];

figure

p = pie(value2);

pPatch = findobj(p, 'Type','Patch');

cm = colormap(turbo(numel(pPatch))); % Colour Array (Can Be Whatever You Define It To Be)

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

for k = 1:numel(cattxt)

pPatch(k).FaceColor = cm(k,:); % Colour Each Patch Individually

pText(k).String = []; % Delete The 'String' Labels

end

lgd = legend(cattxt, 'Location','eastoutside','FontSize',12);

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Answer 2

Benjamin Kraus 2024-4-26

1
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2014991-pie-chart-creation-with-name-number-and-corresponding-percentage#answer_1448731

在 MATLAB Online 中打开

It is worth checking out the new (as of R2023b) piechart command.

You can read about it here: https://blogs.mathworks.com/graphics-and-apps/2023/11/13/pie-charts-and-donut-charts/

A new feature (added in R2024a) is the LabelStyle property, which can be used to quickly create the labels you were asking about.

x = [1,2,3];

txt = {'Item A';'Item B';'Item C'};

p = piechart(x, txt);

p.LabelStyle = 'namepercent';

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Answer 3

MYBLOG 2023-8-30

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2014991-pie-chart-creation-with-name-number-and-corresponding-percentage#answer_1297476

在 MATLAB Online 中打开

The code you provided is mostly correct, but you can simplify it a bit. Here's how you can achieve the same result with your data:

% Your data

number = [78;79;80;81;82;83;84;85;86;87;88]';

value = [4509;5239;6400;9074;11047;13147;15137;13909;6354;1152;183]';

% Create labels for the pie chart

number2 = cellstr(num2str(number)); % Convert numbers to cell array of strings

% Create the pie chart

p = pie(value);

pText = findobj(p,'Type','text');

percentValues = get(pText,'String');

% Combine labels and percentages

combinedtxt = strcat(number2, ': ', percentValues);

% Set the combined text for each slice

for K = 1:numel(value)

pText(K).String = combinedtxt{K};

end

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