plotting four variable using meshgrid for 3 variables, but i am getting error

2023 8 31
1 个回答
回答已采纳
更新时间：2024 6 5
2 次查看（30 天）
Ran in:

0 个投票

Ran in:
t=0.2;
p=1;
for kx = -3:.1:3
q=1;
for ky = -3:.1:3
r=1;
for kz = -3:.1:3
energy_ary(p,q)= -2*t*(cos(kx)+cos(ky)+cos(kz));
z_ary(r)= kz;
r=r+1;
end
y_ary(q)= ky;
q=q+1;
end
x_ary(p)=kx;
p=p+1;
end
x = x_ary ;
y = y_ary ;
z = z_ary ;
[XX,YY,ZZ] = meshgrid(x,y,z);
EE = energy_ary' ;
surf(XX,YY,ZZ,EE) ;
Error using matlab.graphics.chart.primitive.Surface
Value must be a vector or 2D array of numeric type.

Error in surf (line 145)
hh = matlab.graphics.chart.primitive.Surface(allargs{:});
hold all

 采纳的回答

Walter Roberson
Walter Roberson 2023-8-31

0 个投票

meshgrid with 3 inputs always returns 3 dimensional outputs (unless the third input just happens to be scalar.) So your XX, YY, and ZZ are all going to be 3D. But surf() requires that the first two coordinate systems be either vector or 2D, and that the third coordinates be 2D.
surf() is not suitable for creating 3D cuboid volumes with a value for each interior voxel.
If you have three independent input variables and one dependent output variable, then you should consider: slice or isosurface or volshow

更多回答（0 个）

This question is locked.

类别

在 帮助中心 和 File Exchange 中查找有关 Surface and Mesh Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by