i need to code speed ..anyone can help me? Getting rid of the loop would be a good start

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pipor 2023-9-4

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2016741-i-need-to-code-speed-anyone-can-help-me-getting-rid-of-the-loop-would-be-a-good-start

评论： pipor 2023-9-4

v=[1 0 0 1];
d=[0.3 0 0 0.4]
d = 1×4
    0.3000         0         0    0.4000
n="lp";
count=1;
gg=find(v)
gg = 1×2
     1     4
clear b
g={'Cycle n.',count}
g = 1×2 cell array
    {'Cycle n.'}    {[1]}
j=1; %
j = 1
  for h=1:numel(gg)
    b{j,h}={[g,gg(h),d(gg(h))]};
  end
  

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pipor 2023-9-4

编辑：pipor 2023-9-4

because I'm working on a laptop and on a lot of data it happened that I got the error about the memory..hence thinking about not making three-dimensional matrices

however I am modifying the code..maybe I make it clearer

Bruno Luong 2023-9-4

编辑：Bruno Luong 2023-9-4

But you have very bad start. This data organization is awful. We warn you, with such data you'll have speed, memory, and coding problems later.

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采纳的回答

Bruno Luong 2023-9-4

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2016741-i-need-to-code-speed-anyone-can-help-me-getting-rid-of-the-loop-would-be-a-good-start#answer_1301211

在 MATLAB Online 中打开

clear
v=[1 0 0 1];
d=[0.3 0 0 0.4];
count=1;
gg=find(v);
g={'Cycle n.',count};
j=1;
clear b
for h=1:numel(gg)
    b{j,h}={[g,gg(h),d(gg(h))]};
end
% you want horrible code to store horrible data, here we go
bb = num2cell(num2cell([ repmat(g,[numel(gg) 1])  num2cell([ gg' d(gg)' ])], 2)');
isequal(bb,b)
ans = logical
   1